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fomenos
3 years ago
13

How do I solve this?

Mathematics
2 answers:
vladimir1956 [14]3 years ago
8 0
2a+3bx10^3
2a+3bx1000
2a+3000b
mafiozo [28]3 years ago
5 0
2a+3b(10)³
2a+3000b
2(a+1500b)
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Nathan wants to buy a car that costs $25,920 he has $3,000 as a down payment and his payments will be $450 for 6 years through r
sesenic [268]

he payed  3,000 in hand payment then gave checks per...mnth for 6 years to equal the needed amount


3 0
3 years ago
What is 120000+129 and why answer correctly
Alex Ar [27]

Answer:

120,129

Step-by-step explanation:

7 0
3 years ago
State one rational number between -0.45 and -0.46 (answer must be in decimal form.)
seraphim [82]

A rational number between the two given ones is -0.455, such that:

-0.45 > -0.455 > -0.46

<h3>How to find a rational number between the two given ones?</h3>

A rational number is any number that can be written as a quotient between two integer numbers.

Particularly, any number with a finite number of digits after the decimal point is also a rational number.

So to find a rational number between -0.45  and -0.46 we could se:

-0.455, such that:

-0.45 > -0.455 > -0.46

Learn more about rational numbers:

brainly.com/question/12088221

#SPJ1

6 0
1 year ago
carly walks 30 feet in seven seconds. At this rate, how many minutes will it take for carly to walk a mile if there are 5,280 fe
LenaWriter [7]

Answer:

20.53 minutes

Step-by-step explanation:

Speed = Distance/Time = 30/7

Time = Distance / Speed

= 5280/30/7

= 1232 seconds / 60 = 20.53 minutes

Answered by Gauthmath

4 0
2 years ago
5x+2y=22. -2x+6y=3 What is the X coordinate of the solution. Round to the nearest tenth
just olya [345]
Multiply first example by 3 and subtract by second example, you will get the following:

3*(5x + 2y) = 3*22   =>  3*5x + 3*2y = 66      =>  15x + 6y = 66
now subtraction:
(15x + 6y) - (-2x + 6y) = 66 - 3
15x + 6y + 2x - 6y = 63
15x + 2x + 6y - 6y = 63
17x = 63
x = 63/17 ≈ 3.705..... and as it says to round to the nearest tenth our answer would be: x = 3.7
8 0
3 years ago
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