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fomenos
3 years ago
13

How do I solve this?

Mathematics
2 answers:
vladimir1956 [14]3 years ago
8 0
2a+3bx10^3
2a+3bx1000
2a+3000b
mafiozo [28]3 years ago
5 0
2a+3b(10)³
2a+3000b
2(a+1500b)
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Can you plz help me plz
Harman [31]

Answer:b=16

Step-by-step explanation:trust me bro

6 0
3 years ago
Read 2 more answers
Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a
Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = \frac{1}{6}

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

E(X)=\sum x\cdot P(X=x)

Compute the expected monetary value of a single roll as follows:

E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17

Thus, the expected monetary value of a single roll is $1.17.

7 0
3 years ago
Marna is playing a game where you score −5 points each time youguess the correct answer. The goal is to get the lowest score. To
pishuonlain [190]

She would need to score 16 correct answers, because 80/5 = 16.
8 0
3 years ago
What is x?
Dvinal [7]

Answer:

x= 3/17

Step-by-step explanation:

4x(2x+6) =8x^2(23-5)

8x^2 +24x = 144 x^2

24x = 136 x^2

24= 136 x

x=24/136

x=3/17

4 0
2 years ago
Create an expression equivalent 3x+2x+x
Andru [333]
3x+2x+x=6x


So the answer would be: <em>6x</em>
5 0
2 years ago
Read 2 more answers
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