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Natasha_Volkova [10]

3 years ago

14

Brainliest! 30 points!

1 answer:

Galina-37 [17]3 years ago

3 0

Answer:

the correct answer is c

Step-by-step explanation:

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Name the ordered pairs for the vertices on the figure below

Elanso [62]

Answer:

where is the figure?

Step-by-step explanation:

4 0

2 years ago

Question 14 of 16

Goryan [66]

B, because you would just assume the line continues forever on both sides.

6 0

1 year ago

What is the solution set of 7x 2 + 3x = 0?<br><br> {0, 3/7}<br> {0, -3/7}<br> {0, -4/7}

Burka [1]

Answer:

the answer is b when we have two positives it makes a negitive therefore its b

Step-by-step explanation:

4 0

2 years ago

6. Let f and g be differentiable functions

Julli [10]

Answer:

(b) 1

Step-by-step explanation:

To differentiate $h(x)=f(x)g(x)$ we will need the product rule:

$h'(x)=f'(x)g(x)+f(x)g'(x)$ .

We have $h'(x)=f(x)g'(x)$ , so the following equation is true by the transitive property:

$f'(x)g(x)+f(x)g'(x)=f(x)g'(x)$

By subtraction property we have:

$f'(x)g(x)=0$

Since $g(x) \neq 0$ , then we can divide both sides by $g(x)$ :

$f'(x)=\frac{0}{g(x)}$

$f'(x)=0$

This implies $f(x)$ is constant.

So we have that $f(x)=c$ where $c$ is a real number.

Since $f(0)=1$ and $f(0)=c$ , then by transitive property $1=c$ .

So $f(x)=1$ .

Checking:

$h(x)=1 \cdot g(x)$

$h'(x)=g'(x)=1 \cdot g'(x)$

So the following conditions were met.

5 0

2 years ago

Simplify by dividing (3/5) divided by -4/9

Anton [14]

$\bf \cfrac{3}{5}\div \cfrac{-4}{9}\implies \cfrac{3}{5}\cdot \cfrac{9}{-4}\implies \cfrac{27}{-20}\implies -1\frac{7}{20}$

8 0

2 years ago