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Sholpan [36]
3 years ago
6

Let f(x) be a function with domain [−3,∞) and range (−∞,2). If g(x)= f^−1(x) what is the domain of g(x+4)−7?

Mathematics
1 answer:
Crank3 years ago
7 0

Answer:

  • the domain of the function g(x+4)-7 is (-\infty,-2);
  • the range of the function g(x+4)-7 is [-10,\infty).

Step-by-step explanation:

If the function f(x) has the domain [-3,\infty) and the range (-\infty,2), then the function g(x)=f^{-1}(x) has the domain that id the function's f(x) range and the range that is function's f(x) domain. Therefore,

  • the domain of the function g(x) is (-\infty,2);
  • the range of the function g(x) is [-3,\infty).

The function g(x+4)-7 is the translation of the function g(x) 4 units to the left and 7 units down, hence

  • the domain of the function g(x+4)-7 is (-\infty,-2);
  • the range of the function g(x+4)-7 is [-10,\infty).
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<h2><u>Answer:</u></h2><h2><u></u>\boxed{\boxed{\sf{x=9}}}<u></u></h2><h2><u></u></h2><h2><u>Solution Steps:</u></h2>

______________________________

<h3>1.) Combine x and 3x:</h3>
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<em>  - We combine the </em>(x)<em> variables because to get to the end sum of the equation, there can only be 1 variable. So to get the 1, you combine like terms. </em>

<em />

<h3>2.) Add 19 to both sides:</h3>
  • -19+19= Cancels Out
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<em>  - We do this to get 1 number left over. To do this you do the opposite of what you see. In this case we have a negative 19, so you add 19 on each side of the equals. </em>

<em />

<h3>3.) Divide both sides by 4:</h3>
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<em>  - We do this to get x alone. To do this you do the opposite of what you see. In this case we have </em>4(x)<em> which is multiplying, so you divide by 4 on each side. </em>

<em />

So your answer is \bold{x=9}.

______________________________

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