Answer:
23.75
Step-by-step explanation:
how this helped bye I would appreciated if u liked my comment tho
<h2>
Range of x </h2><h3>
and x>6</h3><h3>
Step-by-step explanation:</h3>
Given AB = 4x + 5, BC = 3x - 2 and AC 9x -5
The sum of the length of any two sides of a triangle is greater than the length of third side.
Case I
AB + BC > AC
⇔4x +5 +3x -2 > 9x -5
⇔7x + 3 >9x - 5
⇔ 7x -9x > -5 -3
⇔-2x > -8
⇔x <4
Case II
if AB+AC > BC
4x +5 +9x -5> 3x -2
⇔13x >3x -2
⇔ 13x -3x> -2
⇔10x > -2
⇔x >
Case III
AC+BC > AB
⇔9x - 5 +3x - 2 > 4x +5
⇔6x -7 > 4x +5
⇔6x -4x >5+7
⇔2x > 12
⇔x > 6
In 19 the height is not missing
<h2><u>
Answer:</u></h2><h2><u>
</u>

<u>
</u></h2><h2><u>
</u></h2><h2><u>
Solution Steps:</u></h2>
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<h3>1.) Combine x and 3x:</h3>
<em> - We combine the </em>
<em> variables because to get to the end sum of the equation, there can only be 1 variable. So to get the 1, you combine like terms. </em>
<em />
<h3>2.) Add 19 to both sides:</h3>
Cancels Out
- <em></em>
<em></em>
<em> - We do this to get 1 number left over. To do this you do the opposite of what you see. In this case we have a negative 19, so you add 19 on each side of the equals. </em>
<em />
<h3>3.) Divide both sides by 4:</h3>
÷ 
÷ 
<em> - We do this to get x alone. To do this you do the opposite of what you see. In this case we have </em>
<em> which is multiplying, so you divide by 4 on each side. </em>
<em />
So your answer is
.
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