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kenny6666 [7]
4 years ago
7

Which are correct represents of the inequality 6x>3+4(2x-1)

Mathematics
1 answer:
Natasha_Volkova [10]4 years ago
7 0

Answer:

Step-by-step explanation:

In order to check the different representations, we first simplify the inequality: 6x ≥ 3 + 4(2x - 1) 6x ≥ 3 + 8x - 4 1 ≥ 2x 1/2 ≥ x Looking at the simplification process, we see that the first and second options are correct representations. Moreover, if we plot the simplified inequality on a number line, then we see that the third representation is also correct. Therefore, the first, second and third representations of the inequality are correct

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<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%7Bx%7D%20" id="TexFormula1" title="f(x) = \sqrt{x} " alt="f(x) =
Georgia [21]

Answer:    \dfrac{1}{2\sqrt x}

<u>Step-by-step explanation:</u>

\lim_{h \to 0} f(x)=\dfrac{f(x+h)-f(x)}{h}

f(x) = \sqrt x\\

f(x+h) = \sqrt{x+h}

\lim_{h \to 0} f(x)=\dfrac{\sqrt{x+h}-\sqrt x}{h}

                   =\dfrac{\sqrt{x+h}-\sqrt x}{h}\bigg(\dfrac{\sqrt{x+h}+\sqrt x}{\sqrt{x+h}+\sqrt x}\bigg)

                   =\dfrac{(x + h)-(x)}{h(\sqrt{x+h}+\sqrt x)}

                   =\dfrac{h}{h(\sqrt{x+h}+\sqrt x)}

                   =\dfrac{1}{\sqrt{x+h}+\sqrt x}

                  =\dfrac{1}{\sqrt{x+0}+\sqrt x}

                  =\dfrac{1}{2\sqrt x}

4 0
4 years ago
Not sure need help ​
WITCHER [35]

Answer:

the circumference is 31.4159 (or 31.42)

5 0
3 years ago
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Answer:

10%

Step-by-step explanation:

30/300 people like hip-hop

So, 1/10 or 10% like hip-hop

7 0
3 years ago
Read 2 more answers
Briana drew a rectangle with a width 5 inches shorter than its length. She measured the perimeter of the rectangle and found it
Zigmanuir [339]
P = 2(L + W)
P = 14
W = L - 5

14 = 2(L + L - 5)
14 = 2(2L - 5)
14 = 4L - 10
14 + 10 = 4L
24 = 4L
24/4 = L
6 = L.......the length is 6 inches

W = L - 5
W = 6 - 5
W = 1 <=== the width is 1 inch
7 0
3 years ago
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