Answer: the length of the field is 70 yards. The width of the field is 35 yards
Step-by-step explanation:
Let L represent the length of the rectangular athletic field.
Let W represent the width of the rectangular athletic field.
A rectangular athletic field is twice as long as it is wide. This means that
L = 2W
The formula for determining the perimeter of a rectangle is expressed as
Perimeter = 2(L + W)
If the perimeter of the athletic field is 210 yards, it means that
210 = 2(L + W)
L + W = 210/2 = 105
Substituting L = 2W into L + W = 105, it becomes
2W + W = 105
3W = 105
W = 105/3 = 35
L = 2W = 2 × 35
L = 70
Answer: 
Step-by-step explanation:
Given: In triangle HIJ and triangle MNO we have
here, HI and NN are the included side between ∠I & ∠H and ∠N and ∠O.
So , by ASA congruence rule,
ΔHIJ ≅ ΔMNO
So by CPCTC (corresponding parts of the congruent triangles are congruent)
First make it into a decimal then move the decimal place to place to the left.
3 feet is 36 inches (12 inches per foot), so it'd be 36:46. You can simplify this to 18:23, which is the answer. I hope this helps!
