Explain how the complement can be used to find the probability of getting at least one item of a particular type

1 answer:

5 0

The outcome A="At least one" means {1,2,3,4,5......n} where n is the maximum possible outcome.

The only other outcome (B) left (i.e. the complement of the above event "at least one") is (B)={0}.

Therefore, by Kolmogorov's second axiom, A and B are complements, and
P(A)+P(B)=1
therefore
P(A)=1-P(B), or in words,
Probability of outcomes of "at least one" is the complement of the outcome of "0" item.

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3 years ago

The interior angles formed by the sides of a pentagon have measures that sum to 540°. What is the measure of angle B?

patriot [66]

Answer:

m∠B = 110°

Step-by-step explanation:

We know that,

The sum of the measures of the angles in a pentagon is 540°.

So, we get,

130 + (x-5) + (x+30) + 75 + (x-35) = 540

i.e. 3x + (130+30+75) - (5+35) = 540

i.e. 3x + 235 - 40 = 540

i.e. 3x + 195 = 540

i.e. 3x = 540 - 195

i.e. 3x = 345

i.e. x= 115°

Now, as m∠B = (x-5)° = (115-5)° = 110°

Hence, the measure of angle B is 110°.

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3 years ago

Read 2 more answers

Write the standard equation for the hyperbola with the following conditions: vertices: (-2, -3) and (6, -3) foci: (-4, -3) and (

STALIN [3.7K]

Hello,

Vertices are on a line parallele at ox (y=-3)

The hyperbola is horizontal.

Equation is (x-h)²/a²- (y-k)²/b²=1

Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)

Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6

c²=a²+b²==>b²=36-4²=20

Equation is:
$\boxed{ \dfrac{(x-2)^2}{16} - \dfrac{(y+3)^2}{20} =1}

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