U need to work it out and solve it. To find the answer
Answer:
m∠B = 110°
Step-by-step explanation:
We know that,
The sum of the measures of the angles in a pentagon is 540°.
So, we get,
130 + (x-5) + (x+30) + 75 + (x-35) = 540
i.e. 3x + (130+30+75) - (5+35) = 540
i.e. 3x + 235 - 40 = 540
i.e. 3x + 195 = 540
i.e. 3x = 540 - 195
i.e. 3x = 345
i.e. x= 115°
Now, as m∠B = (x-5)° = (115-5)° = 110°
Hence, the measure of angle B is 110°.
Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
Answer:
j:5j/2+5=45 Or j=16 how you put it was a little confusing
The answer is 16 ok its going to help mabye