4x^2-3x+4y^2+4z^2=0
here we shall proceed as follows:
x=ρcosθsinφ
y=ρsinθsinφ
z=ρcosφ
thus
4x^2-3x+4y^2+4z^2=
4(ρcosθsinφ)^2-3(ρcosθsinφ)+4(ρsinθsinφ)^2+4(ρcosφ)
but
ρ=1/4cosθsinφ

hence we shall have:
4x^2-3x+4y^2+4z^2
=1/4cosθsinθ(cosθ(4-3sinφ))+4sin^2(φ)

6 0

2 years ago

Identify the vertex and the y-intercept of the graph of the function y= -0.25(x-4)-2

Gennadij [26K]

The y intercept is -2, but I don't remember how to find the vertex sorry

3 0

2 years ago

Read 2 more answers

What is the solution to e/10>12.50

mrs_skeptik [129]

Answer:

e > 125

Step-by-step explanation:

Given

$\frac{e}{10}$ > 12.50

Multiply both sides by 10 to clear the fraction

e > 125

8 0

2 years ago

Write as a simple fraction for x+3/x-3 - x-2/x+2​

Write as a simple fraction for x+3/x-3 - x-2/x+2