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NemiM [27]
3 years ago
7

What is 2(x-5)-7=x+8 for x

Mathematics
1 answer:
Soloha48 [4]3 years ago
4 0

Answer:x=-9

Step-by-step explanation:First distributive property making 2x and -10 then move the -10 to the other side and do the same with the -7 then move the x to the 2x making x=-9

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the width of a rectangle is 3 units less than the length. if the area is 130 square units, then find the dimensions of the recta
Basile [38]

Answer:

Length = 10

Width = 13

Step-by-step explanation:

If the width of a rectangle is 3 units less than the length and if the area is 130 square units, the length is 10 units and the width is 13 units.

Formula: A=wl

Therefore, you have to find what two numbers multiply together in order to recieve 130 units.

A=wl=13·10=130

4 0
3 years ago
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On the diagram, two angles (<1 and <2) formed by the road, and the borders are congruent.
iren [92.7K]

Answer: they share a road lol

Step-by-step explanation:

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3 years ago
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<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20-22x%3D10%5C%5C" id="TexFormula1" title="x^{2} -22x=10\\" alt="x^{2} -22x=10\\"
Ronch [10]

Answer:

Step-by-step explanation:

x^2 - 22x = 10

Next step is to complete the square on the left hand side of the equation and it would be balanced by adding the same number to the right side of the equation. It becomes

x^2 - 22x + (22/2)^2 = 10 + (22/2)^2

x^2 - 22x + (11)^2 = 10 + (11)^2

x^2 - 22x + (11)^2 = 10 + 121

x^2 - 22x + (11)^2 = 131

x^2 - 22x + 121^2 = 131

(x - 11)^2 = 131

Taking square root of both the left hand side and the right hand side of the equation, it becomes

x - 11 = ±√131

x - 11 = ±11.45

Adding 11 to the left hand side and the right hand side of the equation, it becomes

x - 11 + 11 = ±11.45 + 11

x = 11.45 + 11 or x = -11.45 + 11

x = 22.45 or x = - 0.45

5 0
3 years ago
In a two-digit number, the tens digit is 5 less than the units digit. The number itself is five more than three times the sum of
Luden [163]

Given:

In a two-digit number, the tens digit is 5 less than the units digit.

The number itself is five more than three times the sum of its digits.

To find:

The number.

Solution:

Let the two digit number is ab. So,

ab=10a+b

Tens digit is 5 less than the units digit.

a=b-5       ...(i)

The number itself is five more than three times the sum of its digits.

10a+b=3(a+b)+5

10a+b=3a+3b+5

10a+b-3a-3b=5

7a-2b=5          ...(ii)

Using (i) and (ii), we get

7(b-5)-2b=5

7b-35-2b=5

5b=5+35

5b=40

b=8

Putting b=8 in (i), we get

a=8-5

a=3

Therefore, the required number is 38.

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3 years ago
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Prove the multiple of two consecutive integers is positive
Usimov [2.4K]

Answer:

2×3=6

or 6×5=30

Step-by-step explanation:

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3 years ago
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