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solmaris [256]
3 years ago
7

Write an equation of a line in point-slope form that has a slope of -2 and passes through (5, -1).

Mathematics
2 answers:
svetlana [45]3 years ago
7 0
I hope this helps you

dimulka [17.4K]3 years ago
6 0
The answer is y= -2x +9

The point-slope formula is y-y₁=m(x-x₁)

m=the slope (-2) and the x₁ and y₁ are our given points

So now all we have to do is plug in and we get the equation y+1=-2(x-5)

That can be simplified to y = -2x +9
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2.

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Lady bird [3.3K]

Answer: (A) The image of JKL after a 90° counterclockwise about the origin is shown in figure 1. (B) The image of JKL after a reflection across the y-axis is shown in figure 2.

Explanation:

(A)

From the given figure it is noticed that the coordinate points are J(-4,1), K(-4,-2) and L(-3,-1).

If a shape rotate 90 degree counterclockwise about the origin, then,

(x,y)\rightarrow (-y,x)

J(-4,1)\rightarrow J'(-1,-4)

K(-4,-2)\rightarrow K'(2,-4)

L(-3,-1)\rightarrow L'(1,-3)

Therefore, the vertex of imare are  J'(-1,-4),  K'(2,-4) and  L'(1,-3). The graph is shown in figure (1).

(B)

If a figure reflect across the y-axis then,

(x,y)\rightarrow (-x,y)

J(-4,1)\rightarrow J''(4,1)

K(-4,-2)\rightarrow K''(2,-4)

L(-3,-1)\rightarrow L''(3,-1)

Therefore, the vertex of imare are  J''(4,1),  K''(2,-4) and  L''(3,-1). The graph is shown in figure (2).

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