Question

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Answer 1

Answer: The correct option is last, i.e., 8 over quantity x minus 11, x ≠ 2, x ≠ 11.

Explanation:

The given expression is,

$\frac{8x-16}{x^2-13x+22}$

Use factoring method to factorise the denominator.

$\frac{8x-16}{x^2-13x+22}=\frac{8(x-2)}{x^2-11x-2x+22}$

$\frac{8x-16}{x^2-13x+22}=\frac{8(x-2)}{x(x-11)-2(x-11)}$

$\frac{8x-16}{x^2-13x+22}=\frac{8(x-2)}{(x-11)(x-2)}$

The factors of denominator are (x-11) and (x-2), therefore the function is not defined for x=11 and x=2.

Cancel out the common factor (x-2).

$\frac{8x-16}{x^2-13x+22}=\frac{8}{x-11}$

Therefore, the simplified form of the given expression is 8 over quantity x minus 11, x ≠ 2, x ≠ 11, So the last option is correct.

Answer 2

1) (8x-16) / (x²-13x+22) = (8x-16) / (x-11)(x-2)= 8(x-2)/(x-11)(x-2) = 8/(x-11)
Restriction x ≠ 11 & x ≠ 2

Since both values render the denominator = to Zero & we can't divide by 0