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Snezhnost [94]
2 years ago
8

What are the solutions of the following system? -2x^2 + y=-5 y=-3x^2+5

Mathematics
2 answers:
Ray Of Light [21]2 years ago
8 0

Answer:

c

Step-by-step explanation:

Doss [256]2 years ago
5 0
\begin{cases}-2x^2+y=-5\\y=-3x^2+5\end{cases}\\\\\\
-2x^2+(-3x^2+5)=-5\\\\
-2x^2-3x^2+5=-5\quad|-5\\\\-5x^2=-10\quad|:(-5)\\\\x^2=2\\\\
\boxed{x=-\sqrt{2}\qquad\vee\qquad x=\sqrt{2}}\\\\\\
y=-3x^2+5\qquad\vee\qquad y=-3x^2+5\\\\
y=-3(-\sqrt{2})^2+5\qquad\vee\qquad y=-3(\sqrt{2})^2+5\\\\
y=-3\cdot2+5\qquad\vee\qquad y=-3\cdot 2+5\\\\
y=-6+5\qquad\vee\qquad y=-6+5\\\\
\boxed{y=-1\qquad\vee\qquad y=-1}\\\\\\
\begin{cases}x=-\sqrt{2}\\y=-1\end{cases}\qquad\vee\qquad\begin{cases}x=\sqrt{2}\\y=-1\end{cases}

Answer C.
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How many trucks carried only late variety?
murzikaleks [220]

9514 1404 393

Answer:

  • late only: 15
  • extra-late only: 24
  • one type: 43
  • total trucks: 105

Step-by-step explanation:

It works well when making a Venn diagram to start in the middle (6 carried all three), then work out.

For example, if 10 carried early and extra-late, then only 10-6 = 4 of those trucks carried just early and extra-late.

Similarly, if 30 carried early and late, and 4 more carried only early and extra-late, then 38-30-4 = 4 carried only early. In the attached, the "only" numbers for a single type are circled, to differentiate them from the "total" numbers for that type.

__

a) 15 trucks carried only late

b) 24 trucks carried only extra late

c) 4+15+24 = 43 trucks carried only one type

d) 38+67+56 -30-28-10 +6 +6 = 105 trucks in all went out

8 0
2 years ago
Help with #2, thank you :)
marishachu [46]

Answer:

2^6

Step-by-step explanation:

2^2 + 2^4 = 2^6

4 0
2 years ago
Read 2 more answers
What is the constant of proportionality in this table?
Andreyy89

Answer:

k = 10

Step-by-step explanation:

X progresses by 25, while y progresses by 250.

So divide 250 ÷ 15 and your answer is 10.

6 0
2 years ago
Read 2 more answers
Jason owns a small textile company that produces shirts. On a particular day, Jason has one worker come into the shop to make sh
Vesna [10]

Answer:

Variables:

x → The number of hours the worker worked

y → The number of shirts the worker made.

System fo equations:

\left \{ {{25x+1.75 y=270} \atop {y=5x}} \right.

Step-by-step explanation:

Let be x the number of hours the worker worked and y the number of shirts the worker made.

Since:

  • Jason must pay the worker $25 per hour (which can be represented with 25x).
  • He must pay $1.75 per shirt for material costs (which can be represented with 1.75y).
  • The total expenses were $270.

You can write the following equation:

25x+1.75 y=270

Knowing that the worker created an average of 5 shirts per hour, you can write the other equation:

y=5x

Therefore, with this equations you can set up the following system of equations, which could be used to determine the number of hours the worker worked and the number of shirts the worker made:

\left \{ {{25x+1.75 y=270} \atop {y=5x}} \right.

3 0
2 years ago
Ashton surveyed some of the employees at his company about their cell phone habits. From the data, he concluded that most employ
SOVA2 [1]
It can't be A. since if you only look at managers, you are missing all the sales executives.

It may be C. this option is more random but doesn't guarantee that you will represent both groups of employee's. Also, each time you would conduct the survey, you will receive the exact same results since it is the same people. 

It isn't D. for the exact same reason as A. but you're missing managers now. 

Therefore the answer is B. Some managers and some sales executives selected at random. This way you get a sample from both categories, and within those groups, it is randomly selected.

 I hope this helps!

 
3 0
3 years ago
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