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Sliva [168]
3 years ago
12

Number 14 only. Please I really need help on this.

Mathematics
1 answer:
Zigmanuir [339]3 years ago
4 0

rate of change is the distance divided by minute or whatever measurment your using that changes

-79.9/-18/8=4.25

130.9 is the total change of elevation and 19.125 is the total time of the dive so

130.9/19.125 =6.844repeating

I hope this helps you atleast understand rate of change.

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Write the 5th term in the expansion of (5x-y/2)^7
Nezavi [6.7K]

Answer:

65625/4(x^5)(y²)

Step-by-step explanation:

Using binomial expansion

Formula: (n k) (a^k)(b ^(n-k))

Where (n k) represents n combination of k (nCk)

From the question k = 5 (i.e. 5th term)

n = 7 (power of expression)

a = 5x

b = -y/2

....................

Solving nCk

n = 7

k = 5

nCk = 7C5

= 7!/(5!2!) ------ Expand Expression

=7 * 6 * 5! /(5! * 2*1)

= 7*6/2

= 21 ------

.........................

Solving (a^k) (b^(n-k))

a = 5x

b = -y/2

k = 5

n = 7

Substituting these values in the expression

(5x)^5 * (-y/2)^(7-5)

= (3125x^5) * (-y/2)²

= 3125x^5 * y²/4

= (3125x^5)(y²)/4

------------------------------------

Multiplying the two expression above

21 * (3125x^5)(y²)/4

= 65625/4(x^5)(y²)

5 0
3 years ago
The number 'N' of cars produced at a certain factory in 1 day after 't' hours of operation is given by N(t)=100t-5t^2, 0< or
Luden [163]

Given: C(N) = 15,000 + 8000N <span>

In the above equation simply substitute: 
N(t) = 100t - 5t^2 
for N 

</span>

<span>Therefore:
C(t) = 15,000 + 8000{ 100t-5t^2 } 
C(t) =15,000 + 800,000t - 40,000t^2.</span>

 

at t = 5

C(5) = 15,000 + 800,000*5 - 40,000*(5)^2

<span>C(5) = 3,015,000</span>

7 0
3 years ago
Read 2 more answers
What time is it when the small hand is in between the 8 and 9 and when the big hand is at the 6?
Finger [1]
The time would be 8:30
3 0
3 years ago
2. En un concierto hay 432 personas. Si sabemos que hay 48 mujeres más que hombres,
Tomtit [17]
M = 48+x
h=x
x+48+x = 432
2x +48= 432
x=192
mujeres =240
hombres= 192
6 0
3 years ago
(3a2 + 2ab + 2b) + (5a2 − 3ab + 9)
ivann1987 [24]

Step-by-step explanation:

\tt{(3 {a}^{2}  + 2ab + 2b) + (5 {a}^{2}  - 3ab + 9})

~While adding , the sign of each term of second expression remains same. So, Remove the unnecessary parentheses :

⤑ \tt{3 {a}^{2}  + 2ab + 2b + 5 {a}^{2}  - 3ab + 9}

~Like terms are those which have the same base. Combine the like terms :

⤑ \tt{3 {a}^{2}  + 5 {a}^{2}  + 2ab - 3ab + 2b + 9}

⤑ \sf{8 {a}^{2}  - ab + 2b + 9}

\red{ \boxed{ \boxed{ \tt{ ⟿ Our \: final \: answer : 8 {a}^{2}  - ab + 2b + 9}}}}

Hope I helped ! ツ

Have a wonderful day / night ♡

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

6 0
3 years ago
Read 2 more answers
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