Based on the 5 trials, 1 carton of eggs is expected to contain at least one broken egg, on average
<h3>How to determine the number of cartons</h3>
From the question, we understand that only one of the first 10 double-digit numbers is between 01 and 08
This means that:
The average carton or the expected value of eggs in the simulation is 1
Hence, 1 carton of eggs is expected to contain at least one broken egg, on average
Read more about expected values at:
brainly.com/question/15858152
Answer:
y-(-4)=-6(x-1)
its is either (x-1), or (x+1). Im not sure on the last part
Step-by-step explanation:
hope this helps :3
if it did pls mark brainliest
Correction:
Because F is not present in the statement, instead of working onP(E)P(F) = P(E∩F), I worked on
P(E∩E') = P(E)P(E').
Answer:
The case is not always true.
Step-by-step explanation:
Given that the odds for E equals the odds against E', then it is correct to say that the E and E' do not intersect.
And for any two mutually exclusive events, E and E',
P(E∩E') = 0
Suppose P(E) is not equal to zero, and P(E') is not equal to zero, then
P(E)P(E') cannot be equal to zero.
So
P(E)P(E') ≠ 0
This makes P(E∩E') different from P(E)P(E')
Therefore,
P(E∩E') ≠ P(E)P(E') in this case.
The answer is:
(x-5 - sq root 29) (x-5 + sq root 29)
