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Alja [10]
3 years ago
8

Given directed line segment ab find the coordinates of p such thats the ratio of ap to pd is 2:1

Mathematics
1 answer:
arsen [322]3 years ago
8 0

Answer:

The point P on line AB such that the ratio of AP to PB is 2:1 is P = (0, 3)

Step-by-step explanation:

The dimension of the graph can be taken as 1 box = 1 unit

Therefore;

The coordinates of the point A = (-2, -7)

The coordinates of the point B = (1, 8)

For the a point P that gives the ratio AP to PB = 2:1 is given as follows;

The fraction of AP to AB = 2/(2 + 1)×AB = 2/3 × AB

Which gives;

The coordinate of the point P = (-2 + 2/3×(1 - (-2)), -7 + 2/3×(8 - (-7)))

P = (0, 3)

Therefore;

The coordinates of P such that the ratio of AP to PB is 2:1 is P = (0, 3).

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7 0
3 years ago
Dare to solve it so easy ☺️​
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Answer: 1.23×10¹⁶

Step-by-step explanation:

For this problem, we want to use order of operations to solve.

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Let's first solve the parenthesis.

(9*\frac{999999999}{9+9+9+9+9+9+9+9+9} )^2                [add denominator]

(9*\frac{999999999}{81} )^2                                  [cross multiply]

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1.23×10¹⁶

The ending result is way too large. Therefore, we use scientific notation and get 1.23×10¹⁶.

7 0
3 years ago
PLEASE HELP FOR 87 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!
Anton [14]
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4. y = 3·5ˣ doesn't change in slope, so it essentially is similar to a 5ˣ graph.

5. Should be pretty straight forward.
6. Should be pretty straight forward.
7. Should be pretty straight forward.

8. Since x is the length of the border, calculate the area of the frame and subtract that from the area of the square painting. (Remember that the length of the square painting is x - 8, not x - 4)

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11 - 25 are pretty much similar to each other.
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4 years ago
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6 0
3 years ago
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4 years ago
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