give me brainliest answer
Answer:
a) The distance of the light's base from the bottom of the building is approximately: 5.2 ft
b) The length of the beam is approximately: 10.4 ft
Step-by-step explanation:
First, we have to recognize that we may draw a right triangle to picture our problem. Then, in order to find out the distance of the light's base from the bottom of the building, we need to use the tangent trigonometric function:
tan(angle) = opposite side / adjacent side
We know the angle and the opposite side and we want to find the adjacent side:
adjacent side = opposite side / tan(angle) = 9 ft / tan(60°) = 9 ft / = 9 ft / 1.73 = 5.2 ft
In order to find the length of the light beam, we use Pythagoras Theorem:
leg1²+leg2² = hyp²
Since the length of the beam corresponds to the hypotenuse and since we already know the length of the two legs, it is just a matter of substituting the values:
hyp = square_root(leg1²+leg2²) = square_root(9² + 5.2²) ft = square_root(108.4) ft = 10.4 ft
First subtract 11b from both sides and then 11b would cancel out and the 14 would be 3b and then you subtract 3 from both sides and so it would be 3 so you divide 3b by 3 so it would be 3 greater than or equal to b.
Answer:
Step-by-step explanation:
MN // PO
∠OMN =∠POM { alternate interior angles}
∠OMN = 34
∠PMO + ∠OMN + ∠1 = 180 {STRAIGHT LINE}
22 + 34 +∠1 = 180
56 +∠1 = 180
∠1 = 180 - 56
∠1 = 124
∠OPM =∠1 { Corresponding angles, PO//MN AND PM IS TRANSVERSL}
∠OPM = 124
