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zmey [24]
2 years ago
14

Which is an

Mathematics
1 answer:
Andreyy892 years ago
5 0
(Answer 2,770) (estimation: 3,000)
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The population of a town is increasing by 300 inhabitants each year. If its population at the beginning of 1990 was 21,152, what
babunello [35]

Answer:

Step-by-step explanation:

You take the starting year of 1990 and subtract it from 1999 to get the year span of 9,

You then take the amount per year the population goes up by which is 300, so 300 multiplied by 9 is 2,700

You add 2,700 to 21,152 to get B-23,852

8 0
3 years ago
Simplify -4(3-1)+2 <br><br>​
nikdorinn [45]

To solve this you must use the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

First we have parentheses.

-4(3 - 1) + 2

3 - 1 = 2

-4(2) + 2

We have no exponents so go on to multiplication

-4(2) + 2

-4 * 2 = -8

-8 + 2

No division so go to addition

-8 + 2

When adding a positive number with a negative number you will act as if you are subtracting the two numbers, then take the sign of the largest number  (disregarding the signs). In this case the largest number is 8 and its sign is negative. Your answer will have a negative sign.

-6

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0
3 years ago
A 36-foot cable is cut into two pieces. One piece is three times as long as the other piece. How long is the longer piece?
ASHA 777 [7]
It's 27 or 30 brainiest please
8 0
3 years ago
What is the value of x ? round your answer to the nearest tenth .
djverab [1.8K]

Answer:

39 maybe i don't know

Step-by-step explanation:

4 0
3 years ago
If a polynomial function f(x) has roots –8, 1, and 6i, what must also be a root of f(x)? A. –6
anyanavicka [17]

Answer:

-6i

Step-by-step explanation:

Complex roots always come in pairs, and those pairs are made up of a positive and a negative version. If 6i is a root, then its negative value, -6i, is also a root.

If you want to know the reasoning, it's along these lines: to even get a complex/imaginary root, we take the square root of a negative value. When you take the square root of any value, your answer is always "plus or minus" whatever the value is. The same thing holds for complex roots. In this case, the polynomial function likely factored to f(x) = (x+8)(x-1)(x^2+36). To solve that equation, you set every factor equal to zero and solve for the x's.

x + 8 = 0

x = -8

x - 1 = 0

x = 1

x^2 + 36 = 0

x^2 = -36 ... take the square root of both sides to get x alone

x = √-36 ... square root of an imaginary number produces the usual square root and an "i"

x = ±6i

6 0
2 years ago
Read 2 more answers
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