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4 years ago

A sporting goods store is having a sale. A pair of skates normally sells for

Mathematics

1 answer:

melomori [17]4 years ago

8 0

Answer:

$150

Step-by-step explanation:

The discounted price is ...

$200 - 25% × $200

= $200(1 -25%) = $200×0.75

= $150

The discounted price is $150.

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Last week Mark ran 31 miles more than Jack. Mark ran 46 miles .How many miles did Jack run

Levart [38]

You take what Mark ran, 46 miles, and you see that Mark ran 31 more miles than Jack, so the equation would be 46-31, which would be 15 miles. So, Jack ran 15 miles.

8 0

3 years ago

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AYO PLEASE HELP ILL GOVE YOU BRAINLIEST

tamaranim1 [39]

it's a i think, hope this helps

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3 years ago

Pls help with both the equations

jeka57 [31]

Answer:

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3 years ago

An observer standing on a cliff 320 feet above the ocean measured angles of depression of the near and far sides of an island to

Gnesinka [82]

Answer:

154.10 Feets

Step-by-step explanation:

Given the following :

Height (h) of cliff = 320 feet

Angle of depression of near side = 16.5°

Angle of depression of far side = 10.5°

Using trigonometry :

We can obtain x and y as shown in the attached picture :

Tanθ = opposite / Adjacent

Adjacent = height of cliff = 320 Feets

For the near side :

Tanθ = opposite / Adjacent

Tan (16.5°) = x / 320

0.2962134 = x / 320

x = 0.2962134 * 320

x = 94.788318 Feets

For the far side :

Tanθ = opposite / Adjacent

Tan (10.5°) = x / 320

0.1853390 = x / 320

x = 0.1853390 * 320

x = 59.308494 Feets

Length of island = (59.308494 + 94.788318) feet

= 154.10 Feets

5 0

3 years ago

PLS HELP ME!!! The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of

Pachacha [2.7K]

Hello!

The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³

Data: (Cone)

h (height) = 12 cm

r (radius) = 4 cm (The diameter is 8 being twice the radius)

Adopting: $\pi \approx 3.14$

V (volume) = ?

Solving: (Cone volume)

$V = \dfrac{ \pi *r^2*h}{3}$

$V = \dfrac{ 3.14 *4^2*\diagup\!\!\!\!\!12^4}{\diagup\!\!\!\!3}$

$V = 3.14*16*4$

$\boxed{V = 200.96\:cm^3}$

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 4 cm

Adopting: $\pi \approx 3.14$

If: We know that the volume of a sphere is $V = 4* \pi * \dfrac{r^3}{3}$ , but we have a hemisphere, so the formula will be half the volume of the hemisphere $V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}$