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Zepler [3.9K]
4 years ago
5

Which algebraic expression is a polynomial with a degree of 3?

Mathematics
2 answers:
Rina8888 [55]4 years ago
7 0

Answer:

it's b

Step-by-step explanation:

Irina18 [472]4 years ago
5 0

Option a: 4x^{3} -\frac{2}{x}

Option b: 2y^{3} +5y^{2} -5y

Option c: 3y^{3} -\sqrt{4y}

Explanation:

The highest degree of a polynomial is the largest exponent of that variable.

Now, we shall determine the polynomial with degree 3.

Option a: 4x^{3} -\frac{2}{x}

From the expression 4x^{3} -\frac{2}{x}, the highest degree of the polynomial is 3.

Hence, 4x^{3} -\frac{2}{x} is a polynomial with a degree of 3.

Hence, Option a is the correct answer.

Option b: 2y^{3} +5y^{2} -5y

From the expression 2y^{3} +5y^{2} -5y, the highest degree of the polynomial is 3.

Hence, 2y^{3} +5y^{2} -5y is a polynomial with a degree of 3.

Hence, Option b is the correct answer.

Option c: 3y^{3} -\sqrt{4y}

From the expression 3y^{3} -\sqrt{4y}, the highest degree of the polynomial is 3.

Hence, 3y^{3} -\sqrt{4y} is a polynomial with a degree of 3.

Hence, Option c is the correct answer.

Option d: -xy\sqrt{6}

From the expression -xy\sqrt{6}, the highest degree of the polynomial is 1.

Hence, -xy\sqrt{6} is a polynomial with degree 1.

Hence, Option d is not the correct answer.

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beks73 [17]

Answer:

The answer is the first R

Step-by-step explanation:

Because I said so

4 0
3 years ago
You are riding a roller coaster when a shoe falls off your foot. The function y=300−16t2 represents the height y (in feet) of th
Juli2301 [7.4K]

Answer:

Time to land on 11ft is 4.25 seconds

Step-by-step explanation:

Given

y = 300 - 16t^2

Required

Solve for t when height is 11ft

This implies that y = 11

So: substitute 11 for y in y = 300 - 16t^2

11 = 300 - 16t^2

Collect Like Terms

16t^2 = 300 - 11

16t^2 = 289

Express both sides as squares

4^2 * t^2 = 17^2

(4t)^2 = 17^2

Take square roots of both sides (ignore negative)

4t = 17

Solve for t

t = \frac{17}{4}

t = 4.25

Hence, time to land on 11ft is 4.25 seconds

8 0
3 years ago
1.Define phase shift. Could every sine function be expressed as a phase shifted cosine function? Explain.
Ann [662]
A phase shift is defined as the a<span>mount of x by which sinusoid is shifted to the left or right.
 
And yes, </span><span>every sine function be expressed as a phase shifted cosine function:
</span>
sin(t)=cos(90-t)

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
4 0
3 years ago
PLEASE HELP FAST
Pachacha [2.7K]
C, I was in class this morning and we say the formula for this is $6000 x 1.15 to the power of 5. That is $12068.14

Hope I could help :)

5 0
3 years ago
I NEED HELP !!! 30 points!!!! and brainliest :)<br><br>please give sensible answer :(<br><br><br>​
Allushta [10]

Answer:

Step-by-step explanation:

9) PQR Is an isosceles triangle

=> ∠PRQ = (180° - x)/2

PRS is an isosceles right triangle

=> ∠PRS = 45°

Have: ∠PRS + ∠PRQ = 115°

=> \frac{180-x}{2}+45=115 \\

=> 180 - x = (115 - 45).2 = 140

<=> x = 180 - 140 = 40

10) ABD is an isosceles right triangle => ∠ABD = 45°

BCD is an equilateral triangle => ∠CBD = 60°

have: x = ∠ABD + ∠CBD = 45° + 60° = 105°

11) have: x = y (2)

PQT is an isosceles triangle => ∠PQT = 180 - 70.2 = 40

QTS   is an isosceles triangle => ∠TQS = 180 -2x

QRS   is an isosceles triangle => ∠RSQ = y

have: 40 + 180 - 2x + y = 180 => 2x - y = 40 (1)

(1)(2) => \left \{ {{y=x} \atop {2x-y=40}} \right.\\\\=> \left \{ {{x=40} \atop {y=40}} \right.

=> x + y = 80

12) EFJ Is an equilateral  triangle => ∠FJE = 60

∠FJE is the outer angle of the triangle FHJ but FHJ is an isosceles triangle

=> 60 = 2.∠JHF => ∠JHF = 30°

∠JHF is the outer angle of the triangle FHG

=> 30° = 2x

<=> x = 15°

7 0
3 years ago
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