<h3>
Answer: -3x-3y=-30= x=−y+10 </h3><h3>x+y+10= x=−y+10</h3>
If the polynomial is of the form x^2+bx+c (ie., no factor in front of the x^2!!) then you can look for numbers that add up to b and multiply to c.
So in this case: what two numbers, when added, give -2 and when multiplied, give 1? A little trial and error gives you -1 and -1.
So the factorization is (x-1)(x-1). This is zero for x=1. There is only one zero.
Answer:
A) 7x^3 + 13x^2 + 8x + 9
Step-by-step explanation:
(3x^2 + 2x + 7x^3) + (10x^2 + 6x + 9)
I like to line them up vertically
7x^3 +3x^2 + 2x
+ (10x^2 + 6x + 9)
-----------------------------------
7x^3 +13x^2 +8x +9
Answer:
Make an eqaution from here.
Let’s make evening 2 “x”
So the first evening has 9 less then the secon evening so…
x-9
Of course theres the second evening (x).
X-9+x
Then the third evening has 4 times as much as the second meeting so…
x-9+x+4x
And when solved, it has to equal 105.
So solve from here.
Combine like terms.
6x-9=105
Isolate
6x=114
x= 19
First evening is 9 less then 19, so 10.
The second evening was 19 calls.
The third evening was 4 times the second evening so, 19*4= 76
1st night = 10
2nd night= 19 calls
Thrid night= 76 calls
x = cos (47) = Pi/3, cos 47 = X/3
Step-by-step explanation:
x = 2.05, 2.05 (2.05)²
