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noname [10]
3 years ago
5

Can somebody help me pleasse?

Mathematics
2 answers:
Elenna [48]3 years ago
6 0

yes! what do you need?

Step-by-step explanation:

Luda [366]3 years ago
4 0
Help! I need somebody help!!! Not just anybody!!! Help!
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What are the answers I need help ?
olchik [2.2K]

Answer:

I can't see -_-

Step-by-step explanation:

I can't -_-

7 0
4 years ago
The population of a community is known to increase at a rate proportional to the number of people present at time t. The initial
maks197457 [2]

Answer:

The initial population P0 is 7500

Step-by-step explanation:

First of all, we are told that the population is proportional to time. This means that as time goes by, the population will increase. This type of relationship between two variables has the form of a linear equation expressed as:

y = mx + b,

where m is the slope of the curve and b is the intercept of it.

In this case we can state the following equation:

P = mt + P0

Where P is the population at a certain time "t", "m" is the slope of the curve, "t" is the time (this is the independent variable) and P0 is the intercept of the curve and represents the initial population.

Once we state the equation, let's see what we know:

If t = 0, then P = P0

If t = 3, then P = 12000 just as we are told

and if t = 5, then P = 2 P0 because after five years the population has doubled compared to the initial population (P0).

From the definition of the slope of the curve:

(Y2 - Y1)/(X2-X1) = m

and using the data described before we can formulate the slope value:

m = (2P0 - P0)/(5-0)

m = (2P0 - P0)/5

m = P0/5

Then, let's replace the value of m in the following equation:

P = mt + P0

12000 = (P0/5) × 3 + P0 → This is the equation presented when 3 years has gone by and we now have a population of 12000.

12000 = (3/5) P0 + P0

12000 = (8/5) P0

12000×5/8 = P0 = 7500

Then we can calculate the value of the slope m:

m = P0/5

m = 7500/5 = 1500

Now, knowing the value of m and the initial population P0 we are able to calculate the population at any value of "t".

6 0
3 years ago
Using triangle A B C as the pre-image and the origin as the center of dilation, which coordinate point is not a coordinate of a
Ostrovityanka [42]

Answer:

The correct option is:

begin ordered pair 4 comma 12 end ordered pair i.e. (4,12).

Step-by-step explanation:

We are given the coordinates of the point A,B and C of the triangle ΔABC as:

A(-1,3) , B(2,1) and C(-2,-1).

Now it is given that there is dilation of this triangle about the origin with a scale factor of 4.

This means that the change in the coordinates after the transformation is given by the rule:

(x,y) → (4x,4y)

As A → A' , B → B' and C → C'

Hence the coordinates A',B' and C' are given by:

A' are (4×-1,4×3)=(-4,12)

B' are (4×2,4×1)=(8,4)

and C' are (4×-2,4×-1)=(-8,-4).

<em>Hence the coordinate point which is not a coordinate of dilation is:</em>

<em>begin ordered pair 4 comma 12 end ordered pair  i.e. (4,12)</em>

3 0
3 years ago
For a dilation with a scale factor less than 1, how do the angles and side lengths of the preimage relate to the angles and side
kakasveta [241]

Answer: option A

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Need some help with this question
Aliun [14]

3 1/3, 7-3 2/3=3 1/3, use absolute value

4 0
3 years ago
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