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3 years ago

How do you write 38,956 in expanded form?

Mathematics

2 answers:

Trava [24]3 years ago

8 0

30,000+8,000+900+50+6

Yuki888 [10]3 years ago

5 0

38,956 in expanded form is (3 x 10,000)+(8 x 1,000)+(9 x 100)+(5 x 10)+(6 x 1).

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Step-by-step explanation:

You divide 156 by 3 and you get your answer 52. Therefore, each kid got 52 toys each.

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-1.2 is equal to or smaller than -0.8r<br><br> What is r bigger than

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A certain type of automobile battery is known to last an average of 1140 days with a standard deviation of 80 days. If 400 of th

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Answer:

Mean = $\mu = 1140$

Standard deviation = $\sigma = 80$

Find the probabilities for the average length of life of the selected batteries.

A)The average is between 1128 and 1140.

We are supposed to fidn P(1128<x<1140)

Formula : $Z=\frac{x-\mu}{\sigma}$

At x = 1128

$Z=\frac{1128-1140}{80}$

$Z=-0.15$

Refer the z table for p value

P(x<1128)=0.4404

At x = 1140

$Z=\frac{1140-1140}{80}$

$Z=0$

Refer the z table for p value

P(x<1140)=0.5

So,P(1128<x<1140)=P(x<1140)-P(x<1128)=0.5-0.4404=0.0596

Hence the probabilities for the average length of life of the selected batteries is between 1128 and 1140 is 0.0596

B)The average is greater than 1152.

P(x>1152)

At x = 1128

$Z=\frac{1152-1140}{80}$

$Z=0.15$

Refer the z table for p value

P(x<1152)=0.5596

So,P(x>1152)=1-P(x<1152)=1-0.5596=0.4404

Hence the probabilities for the average length of life of the selected batteries is greater than 1152 is 0.4404

C) The average is less than 940.

P(x<940)

At x = 940

$Z=\frac{940-1140}{80}$

$Z=-2.5$

Refer the z table for p value

P(x<940)=0.5596

Hence the probabilities for the average length of life of the selected batteries is less than 940 is 0.5596

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3 years ago