Answer: In 2008 the population was 21,525,144
Step-by-step explanation:
You need to use the following formula for Exponential decay:
Where 
is the initial population in the year 0, 
is the rate of decay and 
is the time.
In this case, you can identify that:
Therefore, substituting these values into the formula for Exponential decay, you get:
Then, in 2008 the population was 21,525,144
<span>A + c + 2b = a + 2b + c
Commutative property
hope that helps</span>
Answer: 0.02
Step-by-step explanation:
OpenStudy (judygreeneyes):
Hi - If you are working on this kind of problem, you probably know the formula for the probability of a union of two events. Let's call working part time Event A, and let's call working 5 days a week Event B. Let's look at the information we are given. We are told that 14 people work part time, so that is P(A) = 14/100 - 0.14 . We are told that 80 employees work 5 days a week, so P(B) = 80/100 = .80 . We are given the union (there are 92 employees who work either one or the other), which is the union, P(A U B) = 92/100 = .92 .. The question is asking for the probability of someone working both part time and fll time, which is the intersection of events A and B, or P(A and B). If you recall the formula for the probability of the union, it is
P(A U B) = P(A) +P(B) - P(A and B).
The problem has given us each of these pieces except the intersection, so we can solve for it,
If you plug in P(A U B) = 0.92 and P(A) = 0.14, and P(B) = 0.80, you can solve for P(A and B), which will give you the answer.
I hope this helps you.
Credit: https://questioncove.com/updates/5734d282e4b06d54e1496ac8
Answer:
1,000
Step-by-step explanation:
200 divided by 14=14.285
14.285 times 70 equals 1000
The GCF for 44, 77,210, and 126 is 1 . I know this because other than one they have none of the same factors that go into each of the numbers.
Hope this helps!! Please rate em the brainliest answer!!!
