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attashe74 [19]
4 years ago
8

How are the coordinates of the new point found if it is translated right/left and up/down?

Mathematics
1 answer:
Allushta [10]4 years ago
3 0
Stat with x with = 0, and y = 0 , x is the horizontal axis and y is the vertical axis.
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Two functions, A and B, are described as follows: Function A y = 8x + 3 Function B The slope is 1 and the y-intercept is 4. How
____ [38]
1. Subtract 3 from both sides:
y - 3 = 8x
2. Divide both sides by 8:
y - 3/8 = x
3. Switch sides:
x = y - 3/8
8 0
3 years ago
Brian, Chris, and Damien took a math test that had 20 questions. The number of questions Brian got right is 14 more than the num
shepuryov [24]

<em><u>Question:</u></em>

Brian, Chris, and Damien took a math test that had 20 questions. The number of questions Brian got right is 14 more than 1/4 the number of questions Chris got right. Damien correctly answered 2 less than 5/4 the number of questions Chris answered correctly. If Brian and Damien have the same score, which statement is true?

A) Brian and Damien both answered 2 fewer questions correctly than Chris did.

B) Brian and Damien both answered 4 more questions correctly than Chris did.

C) Brian and Damien both answered 2 more questions correctly than Chris did.

D) Brian and Damien both answered 4 fewer questions correctly than Chris did.

<em><u>Answer:</u></em>

Option C

Brian and Damien both answered 2 more questions correctly than Chris did

<em><u>Solution:</u></em>

Let "x" be the number of correct answers of Brian

Let "y" be the number of correct answers of Chris

Let "z" be the number of correct answers of Damien

<em><u>The number of questions Brian got right is 14 more than 1/4 the number of questions Chris got right</u></em>

x = 14 + \frac{1}{4}y\\ ---------- eqn 1

<em><u>Damien correctly answered 2 less than 5/4 the number of questions Chris answered correctly</u></em>

z = \frac{5}{4}y - 2 ---------- eqn 2

<em><u>Brian and Damien have the same score</u></em>

x = z -------- eqn 3

Therefore,

14 + \frac{1}{4}y = \frac{5}{4}y - 2\\\\\frac{5}{4}y - \frac{1}{4}y = 14+2\\\\y = 16

<em><u>Substitute y = 16 in eqn 1</u></em>

x = 14 + \frac{16}{4}\\\\x = 14 + 4\\\\x = 18

Therefore, by eqn 3,

z = 18

Thus we get,

Number of correct answers of Brian = 18

Number of correct answers of chris = 16

Number of correct answers of Damien = 18

Therefore, correct statement is:

Brian and Damien both answered 2 more questions correctly than Chris did

5 0
3 years ago
MATLAB Simulation. Develop a Matlab script to simulate the modulation of a 30 kHz carrier with a 0.5 kHz message signal. Use 40%
iren2701 [21]

Answer:

MATLAB code for DSB-SC modulation.

fc=154000; % carrier signal frequency

fm=fc/10; % message signal frequency

fs=100*fc;

t=0:1/fs:4/fm;

xc=cos(2*pi*fc*t);

xm=10*cos(2*pi*fm*t); % amplitude of sinusodial is 10

figure(1)

subplot(2,1,1),plot(t,xc);

title('carrier signal of 154 khz');

xlabel('time (sec)');

ylabel('amplitude');

subplot(2,1,2),plot(t,xm);

title('message signal of 15.4 khz');

xlabel('time (sec)');

ylabel('amplitude');

% DSB-SC MODULATION

z1= xm.*xc;

figure(2)

subplot(2,1,1),plot(t,z1);

title('DSB-SC MODULATION IN TIME DAOMAIN');

xlabel('time (sec)');

ylabel('amplitude');

l1=length(z1);

f=linspace(-fs/2,fs/2,l1);

Z1=fftshift(fft(z1,l1)/l1);

subplot(2,1,2),plot(f,abs(Z1));

title('DSB SC MODULATION IN FREQUENCY DOMAIN');

xlabel('frequency(hz)');

ylabel('amplitude');

axis([-200000 200000 0 3]);

Step-by-step explanation:

6 0
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The answer to this is A
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