Where are your choices? Is there more?
Hello Again! The answer would be C. (8,11)
To confirm we will plug the numbers x = 8, Y = 11
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2x - 5 = y
(2 x 8) - 5 = 11
16 - 5 = 11
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y = x + 3
11 = 8 + 3
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So now you can determine that the answer would be (8,11)
Answer:
-3 1/3
Step-by-step explanation:
The quadratic
... y = ax² +bx +c
has its extreme value at
... x = -b/(2a)
Since a = 3 is positive, we know the parabola opens upward and the extreme value is a minimum. (We also know that from the problem statement asking us to find the minimum value.) The value of x at the minimum is -(-4)/(2·3) = 2/3.
To find the minimum value, we need to evaluate the function for x=2/3.
The most straightforward way to do this is to substitue 2/3 for x.
... y = 3(2/3)² -4(2/3) -2 = 3(4/9) -8/3 -2
... y = (4 -8 -6)/3 = -10/3
... y = -3 1/3
_____
<em>Confirmation</em>
You can also use a graphing calculator to show you the minimum.
Hey there!
It seems as if you found the answer to your problem? If you need any help though, just let me know!
Let me know if you'd like me to explain how I got this answer!
Answer:
24
Step-by-step explanation:
23+4⋅2−7
PEMDAS
Multiply first
23+8−7
Add and subtract from left to right
31-7
24