It would have 0 x-intercepts.
I = 42t
When t = 5, I = 42*5 = 210
When t = 6, I = 42*6 = 252
When t = 7, I = 42*7 = 294
When t = 8, I = 42*8 = 336
When t = 9, I = 42*9 = 378
When t = 10, I = 42*10 = 420
The solution to this equation is: x<7
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Answer:
I would say B because there are 15 1s
