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san4es73 [151]
3 years ago
8

What is 1103857 times 38219847391028474? It is for my math hw.

Mathematics
2 answers:
Dahasolnce [82]3 years ago
6 0

4.2189 is the final answer! :)

diamong [38]3 years ago
4 0
I don't know if this helps but my calculator said 4.2189246e+21
You might be interested in
A swimming pool measures 40 ft long by 20 ft wide. The pool is filled to a depth of 5 ft. Find the volume of the water in the po
madreJ [45]

Answer: 4,000 cubic feet

Step-by-step explanation:

Volume=LWH (Length times width times height, nay base times height)

V=40*20*5

V=40*20*5= 4000

Answer: 4,000 cubic ft.

8 0
3 years ago
Help me 7th grade math please
Stolb23 [73]

Answer: 13.5 ounce bottle for $2.19

a 29.2 ounce bottle for $5.37

The 29.2 ounce bottle is better

Step-by-step explanation:

13.5 ounce bottle for $2.19

a 29.2 ounce bottle for $5.37

find the ratios

13.5/2.19 = $6.16 per unit

29.2/5.37 = $5.44 per unit

3 0
2 years ago
In the given figure, find ∠PQS, if∠PQR = 5x + 25 and∠SQR = 2x + 10.
kramer

Answer:

∠PQS= 3(x +5)

Step-by-step explanation:

∠PQR = 5x + 25

∠SQR+∠PQS= 5x+25

∠PQS = ∠PQR-∠SQR

∠PQS= (5x + 25 )-(2x + 10)

∠PQS = 5x+25 -2x-10

∠PQS= 3x +15

∠PQS= 3(x +5)

3 0
3 years ago
A superhero asked his nemesis how many cats she has. she answered with a riddle "Three-fourths of my cats plus seven" how many c
liq [111]
Let C be the number of cats of the superhero. With this, the number of cats of nemesis have is 3C/4 + 7. The numbers should be equal such that,
                                     C = 3C/4 + 7
The value of C from the equation is 28. Thus, the number of cats of the nemesis is 28. 
6 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
NISA [10]

Answer:   \bold{b)\quad \dfrac{2\pi}{3},\dfrac{4\pi}{3},0}

<u>Step-by-step explanation:</u>

Note the following identities: tan² x = sec²x - 1

                                                 \sec x=\dfrac{1}{\cos}

tan² x + sec x = 1

(sec² x -1) + sec x = 1

sec² x + sec x - 2 = 0

(sec x + 2)(sec x - 1) = 0

sec x + 2 = 0     sec x - 1 = 0

sec x = -2          sec x = 1

\dfrac{1}{\cos x}=-2\qquad \dfrac{1}{\cos x}=1\\\\\cos x=-\dfrac{1}{2}\qquad \cos x=1\\\\x=\dfrac{2\pi}{3}, \dfrac{4\pi}{3}\qquad x=0

8 0
3 years ago
Read 2 more answers
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