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MaRussiya [10]
3 years ago
7

What are the solutions to the quadratic equation 4(x + 2)2 = 36 x = −11 and x = 7 x = −7 and x = 11 x = −5 and x = 1 x = −1 and

x = 5
Mathematics
2 answers:
Dmitriy789 [7]3 years ago
4 0

Answer:

c

Step-by-step explanation:

edge2020

Gnom [1K]3 years ago
4 0

Answer:

c

Step-by-step explanation:

source: trust me bro

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For f(x)=1/x^2-3, find<br> a) f(3)<br> b) f(2+h)<br> Show/explain work
valentina_108 [34]

f(x)=\dfrac{1}{x^2-3}\\\\a)\ f(3)\to\text{put x=3 to the equation of the function f}\\\\f(3)=\dfrac{1}{3^2-3}=\dfrac{1}{9-3}=\dfrac{1}{6}\\\\Answer:\ \boxed{f(3)=\dfrac{1}{6}}\\\\b)\ f(2+h)\to\text{put x=2+h to the equation of a function f}\\\\f(2+h)=\dfrac{1}{(2+h)^2-3}\ \ \ |\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\=\dfrac{1}{2^2+2(2)(h)+h^2-3}=\dfrac{1}{4+4h+h^2-3}=\dfrac{1}{h^2+4h+1}\\\\Answer:\ \boxed{f(2+h)=\dfrac{1}{h^2+4h+1}}

6 0
3 years ago
Evaluate 5! + 2!.<br> Idk what is it
Sedbober [7]

Answer:

122

Step-by-step explanation:

If a number has an explanation point on the side of it, you should multiply all numbers that are equal to are less than that number.

5!=5*4*3*2*1=120\\2!=2*1=2\\120+2=122

4 0
3 years ago
Which graph shows a graph of a circle with equation x 2 + (y+3) 2 =9
Nat2105 [25]
<h2>Answer:</h2>

The graph of the circle is given in the image attached

6 0
3 years ago
Solve for x 3x + 3 − x + (−7) &gt; 6 A. x &gt; (−5) B. x &gt; 2.5 C. x &gt; 5 D. x &lt; 5
denpristay [2]

ANSWER

C. x>5

EXPLANATION

The given inequality is:

3x + 3 − x + (−7) > 6

Deal with the parenthesis first to obtain;

3x + 3 − x −7 > 6

Group similar terms to get:

3x − x> 6-3+7

Combine similar terms to get,

2x \:  > \:  10

Divide both sides by 2 to obtain:

x \:  >  \: 5

The correct choice is C. x>5

3 0
3 years ago
Read 2 more answers
Can anyone do this with steps ..
Harrizon [31]

\\ \sf\longmapsto \displaystyle{\lim_{x\to 0}}\dfrac{sinx-sin3x}{sins3x-sinx}

\boxed{\sf \displaystyle\lim_{x\to 0}\dfrac{f(x)}{g(x)}=\dfrac{\lim_{x\to 0}f(x)}{\lim_{x\to 0}g(x)}}

Now

\\ \sf\longmapsto \displaystyle{\dfrac{\lim_{x\to 0}sinx-\lim_{x\to 0}sin3x}{\lim_{x\to 0}sin3x-\lim_{x\to 0}sinx}}

\boxed{\sf \displaystyle{\lim_{x\to 0}}f(x)=f(a)}

\\ \sf\longmapsto \dfrac{sin0-sin3(0)}{sin3(0)-sin0}

\\ \sf\longmapsto \dfrac{0-0}{0-0}

\\ \sf\longmapsto \dfrac{0}{0}

\\ \sf\longmapsto 0

7 0
3 years ago
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