Question

In Triangle ABC, which trigonometric ratio has the value a/c?

Answer 1

we know that

In the right triangle ABC

$sin(A)=\frac{BC}{AC}= \frac{a}{b}$

$cos(A)=\frac{AB}{AC}= \frac{c}{b}$

$tan(A)=\frac{BC}{AB}= \frac{a}{c}$

$sin(C)=\frac{AB}{AC}= \frac{c}{b}$

$cos(C)=\frac{BC}{AC}= \frac{a}{b}$

$tan(C)=\frac{AB}{BC}= \frac{c}{a}$

therefore

the answer is the option A

$tan(A)$

Answer 2

The answer would be A) tan A, because of SOHCAHTOA (if you don't know this, it means SOH) sin=opposite/hypotenuse, CAH) cos=adjacent/hypotenuse, and TOA) tan=opposite/adjacent).