Answer:
Step-by-step explanation:
Its okay you got this!
This is a SOHCAHTOA problem or a trigonometry problem, which we can only apply to right triangles so...
In this triangle first we need to identify our reference angle, or the angle that we will use to do SOHCAHTOA. In that case our angle here is 53 degrees.
Now lets label our sides relative to that angle:
The hypotenuse is x as the right angle always "points at" the hypotenuse.
Our adjacent side "hugs" our reference angle and we dont need that side here as it isnt labelled to solved for
Our opposite side is all the way across from the angle that we are using so that would be 4
Now knowing that we have a value for our opposite side 4 and our hypotenuse is what we want x
So we are looking for OH and we have that in sine as Sine = Opp/Hyp
Now we plug in:
Sin(of our reference angle) = opp/hyp
Sin(53) = 4/x
Now we multiply by x so:
xsin(53) = 4
Divide by sin(53)
x = 4/sin(53)
x = 5.0085 which is roughly x = 5
Hopefully this makes sense! Let me know if you need help with any other trig related stuff!