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Subtract the 7 from 8, which would then get you...
![n=1](https://tex.z-dn.net/?f=n%3D1)
Answer: 6,048
Step-by-step explanation:
15,000-8,952=6,048
Answer:
It's 5
Step-by-step explanation:
Answer:
The correct answer is "0.3410, 0.4990".
Step-by-step explanation:
Given values are:
![n=150](https://tex.z-dn.net/?f=n%3D150)
![p=\frac{63}{150}](https://tex.z-dn.net/?f=p%3D%5Cfrac%7B63%7D%7B150%7D)
![=0.42](https://tex.z-dn.net/?f=%3D0.42)
At 95% confidence interval,
C = 95%
z = 1.96
As we know,
⇒ ![E=z\sqrt{\frac{p(1-p)}{n} }](https://tex.z-dn.net/?f=E%3Dz%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%20%7D)
By substituting the values, we get
![=1.96\sqrt{\frac{0.42\times 0.58}{150} }](https://tex.z-dn.net/?f=%3D1.96%5Csqrt%7B%5Cfrac%7B0.42%5Ctimes%200.58%7D%7B150%7D%20%7D)
![=1.96\sqrt{\frac{0.2436}{150} }](https://tex.z-dn.net/?f=%3D1.96%5Csqrt%7B%5Cfrac%7B0.2436%7D%7B150%7D%20%7D)
![=0.0790](https://tex.z-dn.net/?f=%3D0.0790)
hence,
The confidence interval will be:
= ![p \pm E](https://tex.z-dn.net/?f=p%20%5Cpm%20E)
= ![0.42 \pm 0.079](https://tex.z-dn.net/?f=0.42%20%5Cpm%200.079)
= ![(0.3410,0.4990)](https://tex.z-dn.net/?f=%280.3410%2C0.4990%29)
D= 1 E=.5 F I cant see the second part