Answer:
∠BAD=20°20'
∠ADB=34°90'
Step-by-step explanation:
AB is tangent to the circle k(O), then AB⊥BO. If the measure of arc BD is 110°20', then central angle ∠BOD=110°20'.
Consider isosceles triangle BOD (BO=OD=radius of the circle). Angles adjacent to the base BD are equal, so ∠DBO=∠BDO. The sum of all triangle's angles is 180°, thus
∠BOD+∠BDO+∠DBO=180°
∠BDO+∠DBO=180°-110°20'=69°80'
∠BDO=∠DBO=34°90'
So ∠ADB=34°90'
Angles BOD and BOA are supplementary (add up to 180°), so
∠BOA=180°-110°20'=69°80'
In right triangle ABO,
∠ABO+∠BOA+∠OAB=180°
90°+69°80'+∠OAB=180°
∠OAB=180°-90°-69°80'
∠OAB=20°20'
So, ∠BAD=20°20'
Answer:
45
Step-by-step explanation:
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Answer:
Step-by-step explanation:
the 3rd one
Yes it does have to be parallel or else it would not be a rectangle.So it is true.
Hope this helped! :)
Using this equation, f(3) = 23.
In order to find the value of f(3), we need to take the f(x) equation and put 3 everywhere we see x. Then we follow the order of operations to solve. So, let's start with the original.
f(x) = 2x^2 + 5sqrt(x - 2)
Now place 3 in for each x.
f(3) = 2(3)^2 + 5sqrt(3 - 2)
Now square the 3.
f(3) = 2(9) + 5 sqrt(3 - 2)
Do the subtraction inside of the parenthesis.
f(3) = 2(9) + 5sqrt(1)
Take the square root
f(3) = 2(9) + 5(1)
Multiply.
f(3) = 18 + 5
And add.
f(3) = 23
