What is sum of 2/4 - 1 3/4
1 answer:
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If a random sample of 20 persons weighed 3,460, the sample mean x-bar would be 3460/20 = 173 pounds.
The z-score for 173 pounds is given by:
Referring to a standard normal distribution table, and using z = 0.66, we find:
Therefore
The answer is: 0.2546
The z-score for 173 pounds is given by:
Referring to a standard normal distribution table, and using z = 0.66, we find:
Therefore
The answer is: 0.2546