(3x^2+9x-6) - (2x^3-4x^2+6x-4)
Short Answer
2x^3+7x^2+3x-2
Step by Step
1.)2x^3 doesn’t subtract from anything because there are no other trinomials
2.)3x^2 - (-)4x^2 = 7x^2 because a double negative cancels out and you end up adding them
3.)9x-6x=3x
4.)-6 - (-)4 = -2 because double negatives cancel out into addition
I can solve it?
take away 11 from both sides to make..
4x = 4
simplified (4 ÷ 4) to make x=1
Answer:
For the first one It would be 8 but the second one id k
Step-by-step explanation:
Answer: speed v= s/t = (460 / 5,75 )km/h
Step-by-step explanation: s= 460 km, t= 5h 45 min = 5,75 h
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
