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Elanso [62]
3 years ago
11

The shortest distance from a point to a straight line is

Mathematics
1 answer:
Dahasolnce [82]3 years ago
5 0

The shortest distance from a point to a straight line is the measurement of the line segment which connects the point to the straight line. This line segment should be perpendicular to the line and is thus called the perpendicular distance. 

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Xelga [282]

Answer:

21x^2+3x+12

Step-by-step explanation:

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Campus sold 400 tickets to a varsity basketball game. Tickets are were $5 for students / children tickets and $9 for adults. The
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x + y = 400

5x + 9y = 2632

Step-by-step explanation:

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Find the distance between the points C(−6, 5)<br> and D(−3, 1)<br> .
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D(-3,1) is the right answer
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Read 2 more answers
The graph of y = x^2 -3 is translated in 4 units to the left of the graph to give the graph A
Vedmedyk [2.9K]

Answer:

a) b = 8, c = 13

b) The equation of graph B is y = -x² + 3

Step-by-step explanation:

* Let us talk about the transformation

  • If the function f(x) reflected across the x-axis, then the new  function g(x) = - f(x)
  • If the function f(x) reflected across the y-axis, then the new  function g(x) = f(-x)
  • If the function f(x) translated horizontally to the right  by h units, then the new function g(x) = f(x - h)
  • If the function f(x) translated horizontally to the left  by h units, then the new function g(x) = f(x + h)

In the given question

∵ y = x² - 3

∵ The graph is translated 4 units to the left

→ That means substitute x by x + 4 as 4th rule above

∴ y = (x + 4)² - 3

→ Solve the bracket to put it in the form of y = ax² + bx + c

∵ (x + 4)² = (x + 4)(x + 4) = (x)(x) + (x)(4) + (4)(x) + (4)(4)

∴ (x + 4)² = x² + 4x + 4x + 16

→ Add the like terms

∴ (x + 4)² = x² + 8x + 16

→ Substitute it in the y above

∴ y = x² + 8x + 16 - 3

→ Add the like terms

∴ y = x² + 8x + 13

∴ b = 8 and c = 13

a) b = 8, c = 13

∵ The graph A is reflected in the x-axis

→ That means y will change to -y as 1st rule above

∴ -y = (x² - 3)

→ Multiply both sides by -1 to make y positive

∴ y = -(x² - 3)

→ Multiply the bracket by the negative sign

∴ y = -x² + 3

b) The equation of graph B is y = -x² + 3

4 0
3 years ago
If f(x) = x2 – 2x, find:<br> X<br> -<br> f(-3) = [?]
Reptile [31]

Did you mean :

f(x) = x² - 2x, find x = -3

f(-3) = (-3)² - 2(-3)

f(-3) = 9 + 6

f(-3) = 15

6 0
3 years ago
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