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Nimfa-mama [501]
3 years ago
5

1. Kamar’s bedroom is shaped like a rectangle that is 16 feet long and 12 feet wide. He wants to put carpet on the floor of the

entire room. How many square feet of carpeting does he need? *
A. 28 feet
B. 28 square feet
C. 192 feet
D. 192 square feet
Mathematics
2 answers:
lutik1710 [3]3 years ago
8 0

Answer:

The answer is D.192 Square Feet because you would multiply 12*16 and you would get 192

Step-by-step explanation:

zhannawk [14.2K]3 years ago
4 0
D. 192 you have to multiply 16 and 12
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Find the two missing terms of the sequence and determine if the sequence is arithmetic, geometric, or neither.
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The sequence is arithmetic.
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Find the coordinates of the vertices of a triangle after a 90 degree rotation counterclockwise about the origin.
Oksana_A [137]

Step-by-step explanation:

The rule for a 90 degree counterclockwise is

(x,y) -> (-y,x)

so

C(-1,2) -> C'(-2,-1)

D(3,5) -> D'(-5,3)

E(1,2) -> E'(-2,1)

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Identify the y-intercept and the constant multiplier. <br><br>y [_] 3 * 6^x​
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24 is the y intercept just multiply
5 0
3 years ago
What is 1/3 of 2/3?​
Alla [95]
1/3 of 2/3

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1/3 x 2/3 = 2/9

5 0
3 years ago
Read 2 more answers
I just need no. a please help me to prove this. ​
OleMash [197]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    and         cos A = cos B · cos C

scratchwork:

  A + B + C = π

               A = π - (B + C)

         cos A = cos [π - (B + C)]                              Apply cos

                    = - cos (B + C)                                    Simplify

                    = -(cos B · cos C - sin B · sin C)          Sum Identity

                    = sin B · sin C - cos B · cos C               Simplify

cos B · cos C = sin B · sin C - cos B · cos C               Substitution

2cos B · cos C = sin B · sin C                                        Addition

                     2=\dfrac{\sin B\cdot \sin C}{\cos B \cdot \cos C}                                     Division

                     2 = tan B · tan C

\text{Use the Sum Identity:}\quad \tan(B+C)=\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}

<u>Proof LHS → RHS</u>

Given:                              A + B + C = π

Subtraction:                     A = π - (B + C)

Apply tan:                  tan A = tan(π - (B + C))

Simplify:                               = - tan (B + C)

\text{Sum Identity:}\qquad \qquad \qquad =-\bigg(\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}\bigg)

Substitution:                        = -(tan B + tan C)/(1 - 2)

Simplify:                               = -(tan B + tan C)/-1

                                            = tan B + tan C

LHS = RHS:   tan B + tan C = tan B + tan C  \checkmark

5 0
3 years ago
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