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Olegator [25]
3 years ago
11

Examine the rotation

Mathematics
1 answer:
Serhud [2]3 years ago
8 0

Answer:

Warning Signs Your Tires Need to Be Rotated

Uneven wear between tires. Tire one side wear. ...

Vehicle vibration. At speeds of 45 mph and higher, you may feel a vibration, which may be caused by uneven wear. ...

Pressure loss. If one tire loses air slowly, yet faster than the others, it may mean too much pressure is put on it.

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5a. $1.50R + $7

5b. 14 rides

Step-by-step explanation:

5b. $28 - $7= $21/1.50= 14

He can go on 14 rides

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2 years ago
Triangle A is the pre-image in a translation, and triangle B is the image, as shown below.
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B. Love miss you have you too she got your
8 0
1 year ago
Need brief explanation about why false is correct
anyanavicka [17]

<u>We are given the equation:</u>

(a + b)! = a! + b!

<u>Testing the given equation</u>

In order to test it, we will let: a = 2 and b = 3

So, we can rewrite the equation as:

(2+3)! = 2! + 3!

5! = 2! + 3!

<em>We know that (5! = 120) , (2! = 2) and (3! = 6):</em>

120 = 2 + 6

We can see that LHS ≠ RHS,

So, we can say that the given equation is incorrect

6 0
2 years ago
PLEASE HELP ASAP!!!!!!!! What is the volume of the prism?
AURORKA [14]
Well the answer is 13 and cannot be written in simplest form because 1/2 and 1/2 have the same denominator so you add them together and you get 2/2 which is a whole number then you add the other whole numbers but don’t forget the new whole number then add the 5 and you get 13 cm
4 0
3 years ago
g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur
sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

\displaystyle V = \pi r^2h

Substitute:

\displaystyle (300) = \pi r^2 h

Solve for <em>h: </em>

\displaystyle \frac{300}{\pi r^2} = h

Recall that the surface area of a cylinder is given by:

\displaystyle A = 2\pi r^2 + 2\pi rh

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for <em>h</em>.

\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r}  \end{aligned}

Find its derivative:

\displaystyle A' = 4\pi r - \frac{600}{r^2}

Solve for its zero(s):

\displaystyle \begin{aligned} (0) &= 4\pi r  - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

\displaystyle  \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2}  \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm}   \end{aligned}

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

7 0
3 years ago
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