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3 years ago

Need brief explanation about why false is correct

Mathematics

1 answer:

anyanavicka [17]3 years ago

6 0

We are given the equation:

(a + b)! = a! + b!

Testing the given equation

In order to test it, we will let: a = 2 and b = 3

So, we can rewrite the equation as:

(2+3)! = 2! + 3!

5! = 2! + 3!

We know that (5! = 120) , (2! = 2) and (3! = 6):

120 = 2 + 6

We can see that LHS ≠ RHS,

So, we can say that the given equation is incorrect

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Jacqueline. Harry, and Stanley bought a pizza pie to share for dinner. Harry ate

Pepsi [2]

Answer:

1/6

Step-by-step explanation:

Harry 1x1/2=1/2

Jacqueline 1/2x1/2=1/4

Stanley 1/3x1/4=1/12

1-1/2-1/4-1/12=

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3 years ago

The function f(x)=2/3x-4 was replaced with f(x+k)=2/3x-6 what is the value of k

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Answer:

The given function $f(x)=\frac{2x}{3}-4$ was replaced with $f(x+k)=\frac{2x}{3}-6$ then the value of k is -3

that is k=-3.

Step-by-step explanation:

The given function is $f(x)=\frac{2x}{3}-4\hfill (1)$

and when x=x+k then $f(x+k)=\frac{2x}{3}-6\hfill (2)$

Now to find the value of k:

Put x=x+k in the function f(x)

$f(x)=\frac{2x}{3}-4$

$f(x+k)=\frac{2(x+k)}{3}-4$

$f(x+k)=\frac{2x+2k}{3}-4\hfill (3)$

Now comparing equations (2) and (3) we get

$f(x+k)=\frac{2x+2k}{3}-4=\frac{2x}{3}-6$

$\frac{2x+2k}{3}-4=\frac{2x}{3}-6$

$\frac{2x+2k}{3}-4-\frac{2x}{3}+6=0$

$\frac{2x}{3}+\frac{2k}{3}-4-\frac{2x}{3}+6=0$

$\frac{2k}{3}+2=0$

$\frac{2k}{3}=-2$

$k=\frac{-2\times 3}{2}$

$k=-3$

Therefore k=-3

Therefore the given function $f(x)=\frac{2x}{3}-4$ was replaced with $f(x+k)=\frac{2x}{3}-6$ then the value of k is -3

that is k=-3.

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