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cestrela7 [59]
4 years ago
15

Find the next two terms for each sequence. Then write its recursive formula 6, 7, 7.5, 7.75

Mathematics
1 answer:
postnew [5]4 years ago
3 0
For each term you're adding half of what you added before. 
So the fifth term is 7.75 + 1/8 = 7.875
the sixth term is 7.875 + 1/16 = 7.9375

a_1 = 6
a_2 = 6 + 1 = 7   =   a_1 + 1 =  a_1 + (½)^0
a_3 = 7 + ½ = 7.5  =   a_2 + ½   = a_2 + (½)^1
a_4 = 7.5 + ¼ = 7.75   =  a_3 + ¼  =  a_3 + (½)^2

So each power of ½ is (n - 2).  The recursive formula is
a_1=6, a_n=a_{n-1}+(\frac{1}{2})^{n-2}
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<h3><u>Given</u>:-</h3>

\rightarrow Side of square = 5.5 units.

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<h3><u>To Find</u>:-</h3>

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\rightarrow \sf{=\: 4 × 5.5}

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Therefore, perimeter of square = 22units.

Now, according to the question, perimeter of square = circumference of the circle. So, circumference of circle = 22units.

Now, using the formula of circumference of circle we can find the radius.

\rightarrow Circumference of circle = \sf{2πr}(putting the value of perimeter)

\rightarrow \sf{22\:=\: 2×3.14×r}

\rightarrow \sf{22\:=\: 6.28×r}

\rightarrow \sf{\frac{22}{6.28}\:=\: r}

\rightarrow \sf{3.50units\:=\: r}

Therefore, radius of circle = 3.50units.

Now, let's find area of the circle:

\rightarrow Area of circle = \sf{πr^2}

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\rightarrow \sf{3.14×3.50^2}

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\rightarrow \sf{38.46unit^2}

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