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Airida [17]
3 years ago
13

Brittany uses the rowing machine and the stair machine at the gym for an exercise program. Her trainer wants her on an exercise

program that meets these two conditions:
After 5 minutes of stretching, Brittany will exercise for 30 minutes, dividing her time between the two types of machines.
Brittany will spend three times as much time on the stair machine as on the rowing machine.
Write an equation.
Mathematics
1 answer:
dangina [55]3 years ago
6 0

Answer:

The equations are: x+ y = 30  and  x = 3y.

Step-by-step explanation:

We are given that Brittany uses the rowing machine and the stair machine at the gym for an exercise program.

Let the time spend by Brittany on the stair machine be represented by the variable x.

and the time spend by Brittany on the rowing machine be represented by the variable y.

Now, there are two conditions stated by her trainer;

  • The first condition states that Brittany will exercise for 30 minutes, dividing her time between the two types of machines, that is;

                           x + y = 30 \text{ minutes}

  • The second condition states that Brittany will spend three times as much time on the stair machine as on the rowing machine, that is;

                                x = 3y

So, the equations are: x+ y = 30  and  x = 3y.

These equations can be solved either using the substitution method or the elimination method.

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Answer:

Step-by-step explanation:

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3 0
3 years ago
A company manufactures and sells x television sets per month. The monthly cost and price-demand equations are
skelet666 [1.2K]

A) The maximum revenue is 450000$

B) The maximum profit is 216000$ when 2400 sets are manufactured and sold for 180$ each

C) When each set is taxed at ​$55​, the maximum profit is 99125$ when 1850 sets are manufactured and sold for 207.5$ each.

A)p(x)=300−(x/20​),

revenue R(x)=p*x

revenue R(x)=300x -(x2/20)

for maximum revenue dR/dx =0 ,

=>300-(2x/20)=0

=>x/10=300

=>x=3000

maximum revenue = R(3000)=300*3000 -(30002/20)

maximum revenue = R(3000)=450000$

B) profit =revenue -cost

profit P(x)=300x -(x2/20)-72000-60x

profit P(x)=240x -(x2/20)-72000

for maximum cost dP/dx =0

240 -(2x/20)=0

x=240*10

x=2400

p(2400)=300−(2400/20​)=180

profit P(2400)=240*2400 -(24002/20)-72000 =216000

The maximum profit is 216000$ when 2400 sets are manufactured and sold for 180$ each

c)

profit =revenue -cost -tax

profit P(x)=300x -(x2/20)-72000-60x-55x

profit P(x)=185x -(x2/20)-72000

for maximum cost dP/dx =0

185-(2x/20)=0

x=185*10

x=1850

p(1850)=300−(1850/20​)=207.5

profit P(1850)=185*1850 -(18502/20)-72000

profit P(1850)=99125$

When each set is taxed at ​$55​, the maximum profit is 99125$ when 1850 sets are manufactured and sold for 207.5$ each.

To know more about maximum profit check the below link:

brainly.com/question/4166660

#SPJ4

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vladimir1956 [14]

Answer:

Step-by-step explanation:

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