Answer:
a.2x+140=200
b.200-140/2
c.30 minutes
Step-by-step explanation:
First, separate the x's and the numbers:
+2x and -x
+3 and +5
Next, solve those sums:
+2x - x = 1x = x
+3 +5 = 8
Answer: A. x+ 8
If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
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If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
Outliers should be excluded when producing a trend line, regardless of the method used.
The student got a score of 100 with no sleep.
This data pair was a rare event.
If the outlier was included, it would cause the trend line to misrepresent the typical data relationship.
I’ll look at your recent posts and see if it’s within my abilities to answer them
