To solve this problem it is necessary to apply the concepts related to the Heisenberg's uncertainty principle. Under this principle we understand the relationship that the minimum range of error in position (x) times the minimum range of error in momentum (p) is, at a minimum, about equal to the Planck constant, mathematically that is,

$\Delta p = \frac{h}{\Delta x}$

Replacing with our values we have,

$\Delta p = \frac{6.63*10^{-34}J\cdot s}{2\pi (53*10^{-12}m)}$

$\Delta p = 1.99*10^{-24} kg\cdot m/s$

Therefore the least uncertainty in any simultaneous measurement of the momentum component px of this electron is $1.99*10^{-24} kg\cdot m/s$

4 0

3 years ago

A model of an atom is shown above. The blue dots represent electrons, and the red dot represents the nucleus. This model accurat

Anvisha [2.4K]

I think the model being described is the Rutherford atom model. This is where he posit that atoms have a nucleus which contains positively charged protons and surrounded by electrons.

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4 0

3 years ago

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What did Rutherford​ model of tje atom include that thompson model did not leave

What did Rutherford model of tje atom include that thompson model did not leave