The vertex form of


where:

We have:

substitute:

The vertex form of f(x):

The value of minimum is equal k.
Therefore:
Explanation:
The question is given below as

We will apply the pedmas rule below
P – Parentheses [{()}]
E – Exponents (Powers and Roots)
MD- Multiplication and Division (left to right) (× and ÷)
AS – Addition and Subtraction (left to right)
By applying the rule, we will have
![\begin{gathered} \begin{equation*} [1+(11+31)\div6)\times5 \end{equation*} \\ [1+\frac{42}{6}]\times5 \\ [1+7]\times5 \\ 8\times5=40 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cbegin%7Bequation%2A%7D%20%5B1%2B%2811%2B31%29%5Cdiv6%29%5Ctimes5%20%5Cend%7Bequation%2A%7D%20%5C%5C%20%5B1%2B%5Cfrac%7B42%7D%7B6%7D%5D%5Ctimes5%20%5C%5C%20%5B1%2B7%5D%5Ctimes5%20%5C%5C%208%5Ctimes5%3D40%20%5Cend%7Bgathered%7D)
Hence,
The final answer is
Answer:
The answer is B the average tax rate
Answer:
= 1.56
Step-by-step explanation:
Hello!
You have two independent samples of fertilizers from distributor A and B, and need to test if the average content of nitrogen from fertilizer distributed by A is greater than the average content of nitrogen from fertilizer distributed by B.
Sample 1
X₁: Content of nitrogen of a fertilizer batch distributed by A
n₁= 4 batches
Sample mean X₁[bar]= 23pound/batch
σ₁= 4 poundes/batch
Sample 2
X₂: Content of nitrogen of a fertilizer batch distributed by B
n₂= 4 batches
Sample mean X₂[bar]= 18pound/batch
σ₂= 5 pounds/batch
Both variables have a normal distribution. Now since you have the information on the variables distribution and the values of the population standard deviations, you could use a pooled Z-test.
Your hypothesis are:
H₀: μ₁ ≤ μ₂
H₁: μ₁ > μ₂
The statistic to use is:
Z= <u> X₁[bar] - X₂[bar] - (μ₁ - μ₂) </u>~N(0;1)
√(δ²₁/n₁ + δ²₂/n₂)
=<u> </u>(<u>23 - 18) - 0 </u> = 1.56
√(16/4 + 25/4)
I hope this helps!
Answer:
25
Step-by-step explanation:
un carro tiene 4 ruedas, entonces divide 100 por 4
100÷4=25