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3 years ago

NEED HELP!!! WILL MARK BRAINLIEST!!!

Mathematics

1 answer:

Tanzania [10]3 years ago

8 0

Answer:

RTA= (x-2)·(x-11/2)/(x-2)(x-4)= (you can simplify again if you want by eliminating both (x-2)

(x-11/2)/(x-4)

Step-by-step explanation:

Ok we need to simplify the expression so:

x^2+3x-10= Bhaskara formula=

-3(±√9-4·1·(-10))/2·1=

X1=(-3+7/2)--> X1=2(R)---> (X-R)--->X-2

X2=(-3-7)/2 --> X2=11/2(R)---> (X-R)--->X-11/2

x^2-6x+8= Bhaskara formula=

6(±√36-4·1·8)/2·1=

X1=(6-2)/2=2--> X1=2(R)---> (X-R)--->X-2

X2=(6+2)/2=2--> X2=4(R)---> (X-R)--->X-4

so, The simplify expression is

(x-2)·(x-11/2)/(x-2)(x-4)=

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Answer:

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General Formulas and Concepts:
Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]:
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Step-by-step explanation:

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Identify given.

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution/u-solve.

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[u] Differentiate [Derivative Rules and Properties]:
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Step 3: Integrate Pt. 2

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[Integrand] Simplify:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-1}{2\sqrt{u}}} \, du$
[Integral] Rewrite [Integration Property - Multiplied Constant]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \frac{-1}{2} \int {\frac{1}{\sqrt{u}}} \, du$
[Integral] Apply Integration Rule [Reverse Power Rule]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = -\sqrt{u} + C$
[u] Back-substitute:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$

∴ we have used u-solve (u-substitution) to find the indefinite integral.

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Learn more about integration: brainly.com/question/27746495

Learn more about Calculus: brainly.com/question/27746485

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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

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