Answer:
the slope of both lines are the same.
Step-by-step explanation:
Given the following segment of the Quadrilateral EFGH on a coordinate Segment FG is on the line 3x − y = −2,
segment EH is on the 3x − y = −6.
To determine their relationship, we can find the slope of the lines
For line FG: 3x - y = -2
Rewrite in standard form y = mx+c
-y = -3x - 2
Multiply through by-1
y = 3x + 2
Compare
mx = 3x
m = 3
The slope of the line segment FG is 3
For line EH: 3x - y = -6
Rewrite in standard form y = mx+c
-y = -3x - 6
Multiply through by-1
y = 3x + 6
Compare
mx = 3x
m = 3
The slope of the line segment EH is 3
Hence the statement that proves their relationship is that the slope of both lines are the same.
To find the lateral area you will find the area of all 4 faces that are perpendicular to the base.
You will multiply the side by the length (front/back) and the side by the width (sides).
12 x 8 = 96
12 x 2 = 24
120 square inches x 2 = 240 square inches
The lateral area is 240 square inches.
The area of the base is 8 x 2 = 16 square inches.
16 x 2 = 32 square inches
240 square inches + 32 square inches = 272 square inches is the surface area.
Answer:
Step-by-step explanation:
Given
← factor numerator and denominator
= 
← cancel common factor (x + 1) on numerator/ denominator
=
Answer:
I'm not ok. that is too expensive
Step-by-step explanation:
Answer:
(B) 5/6 ·13÷4
(C) 5/6 ÷4·13
(D) 5/6 · 13/4
Step-by-step explanation:
Amount of paint per can = ![\[\frac{5}{6}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B5%7D%7B6%7D%5C%5D)
liters.
Number of cans used to paint 4 cars = 13
Total amount of paint used for 4 cars = ![\[13 * \frac{5}{6}\]](https://tex.z-dn.net/?f=%5C%5B13%20%2A%20%5Cfrac%7B5%7D%7B6%7D%5C%5D)
liters.
= ![\[\frac{13 * 5}{6}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B13%20%2A%205%7D%7B6%7D%5C%5D)
liters.
= ![\[\frac{65}{6}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B65%7D%7B6%7D%5C%5D)
liters.
Total amount of paint used for 1 car = ![\[\frac{65}{6} \div 4\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B65%7D%7B6%7D%20%5Cdiv%204%5C%5D)
liters.
= ![\[\frac{65}{24}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B65%7D%7B24%7D%5C%5D)
liters.
Of the given options, option B,C and D correspond to the same value.
