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noname [10]
3 years ago
11

19. The heights, in inches, of players on a basketball team are:

Mathematics
2 answers:
Rom4ik [11]3 years ago
7 0

Hello!

Let's find the mean of each team. Let's add up all of the heights and divide by number of players.

57+63+68+72+50+63+65+69+73+71+60=711

711/11≈64.64

Now we do the same with the soccer team.

49+53+52+52+57+61+55+61+59+61+50+50+51+62+50+57=880

880/16=55

Now we subtract.

64.64-55≈10

Therefore, our answer is D) 10 inches

I hope this helps!

Setler79 [48]3 years ago
4 0

Hi!

Let's find the mean of both data sets.

Basketball

57 + 63 + 68 + 72 + 50 + 63 + 65 + 69 + 73 + 71 + 60 = 711

711/11 = 64.63

Soccer

49 + 53 + 52 + 52 + 57 + 61 + 55 + 61 + 59 + 61 + 50 + 50 + 51 + 62 + 50 + 57 = 880

880/16 = 55

64.63 - 55 = 9.63

The answer is D) 10 inches

Hope this helps! :)

-Peredhel

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Answer:

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Step-by-step explanation:

Given the expression

4\left(2x+7\right)-3\left(x+5\right)

<u>Expand and simplify the expression</u>

4\left(2x+7\right)-3\left(x+5\right)

Expand  4(2x + 7) = 8x + 28                  

4\left(2x+7\right)-3\left(x+5\right)=8x+28-3\left(x+5\right)

Expand  -3(x + 5) = -3x - 15

                                 =8x+28-3x-15

Group like terms

                                  =8x-3x+28-15

Add similar elements:  8x - 3x = 5x

                                   =5x+28-15

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Therefore, we conclude that:

4\left(2x+7\right)-3\left(x+5\right)=5x+13

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Step-by-step explanation:

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We solve using the Trigonometric function of Cosine

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