Given that
log (x+y)/5 =( 1/2) {log x+logy}
We know that
log a+ log b = log ab
⇛log (x+y)/5 =( 1/2) log(xy)
We know that log a^m = m log a
⇛log (x+y)/5 = log (xy)^1/2
⇛log (x+y)/5 = log√(xy)
⇛(x+y)/5 = √(xy)
On squaring both sides then
⇛{ (x+y)/5}^2 = {√(xy)}^2
⇛(x+y)^2/5^2 = xy
⇛(x^2+y^2+2xy)/25 = xy
⇛x^2+y^2+2xy = 25xy
⇛x^2+y^2 = 25xy-2xy
⇛x^2+y^2 = 23xy
⇛( x^2+y^2)/xy = 23
⇛(x^2/xy) +(y^2/xy) = 23
⇛{(x×x)/xy} +{(y×y)/xy} = 23
⇛(x/y)+(y/x) = 23
Therefore, (x/y)+(y/x) = 23
Hence, the value of (x/y)+(y/x) is 23.
Answer:
R theta 1 = 20 x
R theta 2 = 11 x - 6
R ( theta 1 + theta 2) = 31 x - 6 adding equations
R pi = 31 x - 6 since theta 1 + theta 2 = 180 deg
x = (R pi + 6) / 31
This equation depends only R
If one lets R be one then x = (pi + 6) / 31
This would give x = .29489 rad for the value of pi is deg
The numerical value of x appears to depend on the value of R
Answer:
answer is d
Step-by-step explanation:
from question
g(x) = 2(3x) - 4 = 6x - 4
then put x = 1,2,3
so g(x) = 2,8,14
Set up a simple equation with S FOR SALLY AND A FOR ANNA LOOKS LIKE THIS A+(A+.1)=3.16
Answer:
a) H0: 
H1: 
b) 
And the critical values with 
on each tail are:
c) ![t=(10-1) [\frac{1.186}{1.34}]^2 =7.05](https://tex.z-dn.net/?f=%20t%3D%2810-1%29%20%5B%5Cfrac%7B1.186%7D%7B1.34%7D%5D%5E2%20%3D7.05)
d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34
Step-by-step explanation:
Information provided
n = 10 sample size
s= 1.186 the sample deviation
the value that we want to test
represent the p value for the test
t represent the statistic (chi square test)
significance level
Part a
On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:
H0:
H1:
The statistic is given by:
![t=(n-1) [\frac{s}{\sigma_o}]^2](https://tex.z-dn.net/?f=%20t%3D%28n-1%29%20%5B%5Cfrac%7Bs%7D%7B%5Csigma_o%7D%5D%5E2%20)
Part b
The degrees of freedom are given by:
And the critical values with on each tail are:
Part c
Replacing the info we got:
Part d
For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34
