Question

Find the distance between points P(5, 1) and Q(3, 4) to the nearest tenth.

Answer 1

Answer:

≈ 3.6

Step-by-step explanation:

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (P(5, 1) and (x₂, y₂ ) = Q(3, 4)

d = $\sqrt{(3-5)^2+(4-1)^2}$

   = $\sqrt{(-2)^2+3^2}$

   = $\sqrt{4+9}$

    = $\sqrt{13}$ ≈ 3.6 ( to the nearest tenth )