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Dmitry_Shevchenko [17]
3 years ago
14

Balance of trade summarizes

Advanced Placement (AP)
1 answer:
Zepler [3.9K]3 years ago
4 0
C the flow of goods and services. 
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“Let women share the rights and she will emulate the virtues of man; for she will grow more perfect when emancipated.”
Gre4nikov [31]

Answer:

if the women are equal with men, the whole nation will benefit from it.

Explanation:

BOOM!

3 0
3 years ago
Atsand<br>pool pic<br>S<br>pou<br>yo<br>pa<br>ose<br>18<br>e) tudo<br>AJ<br>Acharger​
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Answer:

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Explanation:

no thanks no

3 0
2 years ago
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When was Jesus born for real?
S_A_V [24]

But nobody really knows exactly when Jesus was born. Some scholars think that he was born between 6 B.C. and 4 B.C., based partly on the biblical story of Herod the Great

4 0
3 years ago
The regions bounded by the graphs of y=x2 and y=sin2x are shaded in the figure above. What is the sum of the areas of the shaded
Alex Ar [27]

Answer:

The sum of the area of the shaded regions = 0.248685

Explanation:

The sum of the area of the shaded region is given as follows;

The point of intersection of the graphs are;

y = x/2

y = sin²x

∴ At the intersection, x/2 = sin²x

sinx = √(x/2)

Using Microsoft Excel, or Wolfram Alpha, we have that the possible solutions to the above equation are;

x = 0, x ≈ 0.55 or x ≈ 1.85

The area under the line y = x/2, between the points x = 0 and x ≈ 0.55, A₁, is given as follows

1/2 × (0.55)×0.55/2 ≈ 0.075625

The area under the line y = sin²x, between the points x = 0 and x ≈ 0.55, A₂, is given using as follows;

\int\limits {sin^n(x)} \, dx = -\dfrac{1}{n} sin^{n-1}(x) \cdot cos(x) + \dfrac{n-1}{n} \int\limits {sin^{n-2}(x)} \, dx

Therefore;

A_2 = \int\limits^{0.55}_0 {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_0 ^{0.55}

∴ A₂ =1/2 × ((0.55 - sin(0.55)×cos(0.55)) - (0 - sin(0)×cos(0)) ≈ 0.0522

The shaded area, A_{1 shaded} = A₁ - A₂ = 0.075625 - 0.0522 ≈ 0.023425

Similarly, we have, between points 0.55 and 1.85

A₃ = 1/2 × (1.85 - 0.55) × 1/2 × (1.85 - 0.55) + (1.85 - 0.55) × 0.55/2 = 0.78

For y = sin²x, we have;

A_4 = \int\limits^{1.85}_{0.55} {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_{0.55} ^{1.85} \approx 1.00526

The shaded area, A_{2 shaded} = A₄ - A₃ = 1.00526 - 0.78 ≈ 0.22526

The sum of the area of the shaded regions, ∑A = A_{1 shaded} + A_{2 shaded}

∴ A = 0.023425 + 0.22526 = 0.248685

The sum of the area of the shaded regions, ∑A = 0.248685

8 0
3 years ago
The United States Government has restricted migration with the goal of ensuring that the majority of migrants come from one part
Natasha_Volkova [10]
I would say the answer would be D)
because back then in the 20’s it was politically correct and acceptable to target particular ethnic groups from being able to migrate to your country.
All of the other immigration acts have occurred within the last 50 years or so when it would NOT be acceptable to enforce this kind of exclusion.
hope this helps!
7 0
2 years ago
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