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amid [387]
3 years ago
5

Describe at least three things you can learn about a fetus by taking a sample of the mother's blood.

Biology
1 answer:
chubhunter [2.5K]3 years ago
3 0

Answer:

a) Any genetic disease b) gender of the child/fetus and c) test the blood group type and possible complications

Explanation:

The three things that can learn about a fetus by taking a sample of the mother's blood are as follows -

1. The blood of mother consists of traces of amniotic fluid. This fluid has cells of fetus. Once these cells are extracted the exact gender of the fetus can be determined.  

2. Based on the fetal cell study, the genetic diseases can be determined and necessary precautions can be taken

3. The blood of the fetus can be tested to determine the presence and absence of Rh factor in a particular blood group.  

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In a population of lizards, the allele that causes red eyes (R) is dominant, while the allele that causes green eyes is recessiv
zhenek [66]
The answer is 0.47 or 47%.

Let's first distinguish some terms and their frequencies.
R - the dominant allele that causes red eyes
r - the recessive allele that causes green eyes

Since R is dominant over r, lizards with at least one dominant R allele will have red eyes. Therefore, the genotypes and the phenotypes are as following:
genotypes - phenotypes
RR              - the lizards with red eyes
Rr               - the lizards with red eyes
rr                - the lizards with green eyes

Now, we will use some Hardy-Weinberg equations:
p + q = 1
p² + 2pq + q² = 1

where:
p - the frequency of dominant allele R
q - the frequency of recessive allele r
p² - the frequency of lizards with genotype RR
2pq - the frequency of lizards with genotype Rr
q² - the frequency of lizards with genotype <span>rr
</span>
We are interested in <span>the frequency p of the dominant R allele.
</span>So, we have the frequency (72%) of the lizards that have red eyes. However, lizards with genotypes RR and Rr will have red eyes. Since their frequencies are p² and 2pq, respectively, we have:
p² and 2pq = 72% = 72/100 = 0.72

Now, use this in the equation p² + 2pq + q² = 1:
0.72 + q² = 1
q² = 1 - 0.72 = 0.28

From here, we will calculate q and later p using the formula p + q = 1:
q² = 0.28
q = √0.28 = 0.53

p + q = 1
p + 0.53 = 1
p = 1 - 0.53
p = 0.47
5 0
3 years ago
Read 2 more answers
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