Length (L): L
width (w): (2/3)L
Perimeter (P) = 2L + 2w
390 = 2(L) + 2(2/3)(L)
1170 = 6L + 4L
1170 = 10L
117 = L
width (w): (2/3)L = (2/3)(117) = 2(39) = 78
Answer: width = 78 ft, length = 117 ft
a < -9
Rearrange:
Rearrange the equation by subtracting what is to the right of the greater than sign from both sides of the inequality :
5*a+18-(-27)<0
Step by step solution :
Step 1 :
Pulling out like terms :
1.1 Pull out like factors :
5a + 45 = 5 • (a + 9)
Equation at the end of step 1 :
Step 2 :
2.1 Divide both sides by 5
Solve Basic Inequality :
2.2 Subtract 9 from both sides
a < -9
The diagram where angles 1 and 2 form a linear pair is D. A horizontal line has 1 line extending from it. Angles 1 and 2 are formed.
<h3>What is a linear pair?</h3>
It should be noted that a linear pair simply means angles that are formed when two lines intersect each other at a single point.
In this case, when a horizontal line has 1 line extending from it. Angles 1 and 2 are formed. This depicts a linear pair
In conclusion, the correct option is D.
Learn more about linear pair on:
brainly.com/question/13218054
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Do you mean
![3 \sqrt[3]{125}](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%20)
or
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20)
remember that
![\sqrt[n]{x^m}=x^\frac{m}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%3Dx%5E%5Cfrac%7Bm%7D%7Bn%7D)
resolve the
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D)
part first
![\sqrt[3]{125}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%3D)
![\sqrt[3]{5^3}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%5E3%7D%3D)
so
![3 \sqrt[3]{125}=3*5=15](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%3D3%2A5%3D15%20)
or
![\sqrt[3]{125} =5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20%3D5)
not sure which one you mean
