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4 years ago

2/8 = ?/32 Find the missing numbers that make the fractions equivalent

Mathematics

2 answers:

natali 33 [55]4 years ago

7 0

So since it is 8x4 it will equal 32 now you have to multiply 8x2

horrorfan [7]4 years ago

3 0

The answer is 8/32 because 8 x 4 = 32

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PLEASE HELP!!!!

kondaur [170]

Add 6 to left middle and right
then, divide them all by 3

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3 years ago

What is twice the larger root of x^2-9x+3=0

Vlada [557]

Answer:

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Step-by-step explanation:

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3 years ago

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Please help me . factor. X^2-13x+40

Ainat [17]

Consider the factors of 40: ±1, ±4, ±10, ±5, ±8 ... ±5 and <span>±8 can be manipulated to fit your factorization.

(x - 8)(x - 5) works. -8 - 5 = -13, which is what you need in the middle, and -8*-5 gives you a positive 40.</span>

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3 years ago

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Katie types 600 words in 5 minutes. She compared her typing speed to the record typing speed for her school shown in the table.

Zepler [3.9K]

Answer:

Step-by-step explanation:

since the school recorded is in two minutes, they wrote 420 words, and Katie in 5 minutes wrote 600 words, if you put the average to the person who wrote 420 words in 2 minutes to-

in every too minutes they write 420 words.

so in four minutes they would of typed 840 words, which is more words than Katie in less minutes.

7 0

4 years ago

17.

Marta_Voda [28]

Answer:

a) 50 meters

b) 2354 meters

c) 12 seconds

d) 24.13 seconds

Step-by-step explanation:

Hello!

<h3>a) How far is Lincoln above the ground when he shoots the gun?</h3>

We need to really understand what the variables represent in this question. Given that t is time, and h is height, the time at which he shoots the bullet will be 0, as the bullet hasn't started traveling yet. This means that we can solve for the original height of the bullet by plugging in 0 for time in the equation.

Equation: $h = -16t^2 + 384t + 50$

Plug in 0 for t:

$h = -16t^2 + 384t + 50$
$h = -16(0)^2 + 384(0) + 50$
$h = 50$

The height at which Lincoln shot the bullet is 50 meters.

We can also look at this graphically. The height of origin will simply be when the x-value (in this case t-value) is 0. That means it is the point at which the graph intersects the y-axis, known as the y-intercept.

Standard form of a Parabola: $y = ax^2 + bx + c$

The y-intercept is the "c" value.

Given our equation: $h = -16t^2 + 384t + 50$

The c-value is 50. This proves that the y-intercept is 50.

<h3 /><h3>b)How high does the bullet travel vertically relative to the ground?</h3>

We want to find the highest point of the graph. To do that, we can find the vertex.

We can utilize the Axis of Symmetry (AOS) to find the Vertex.

First, find the AOS using the formula: $AOS = -\frac{b}{2a}$

a = -16
b = 384

Plug it into the formula:

$AOS = -\frac{b}{2a}$
$AOS = -\frac{384}{2(-16)}$
$AOS = \frac{384}{32}$
$AOS = 12$

Plug in 12 for t in the equation:

$h = -16t^2 + 384t + 50$
$h = -16(12)^2 + 384(12) + 50$
$h = -2304 + 4608 + 50$
$h = 2304+50$
$h = 2354$

Therefore, the highest point of the bullet is 2354 meters.

<h3>c)How long does it take the bullet to reach its greatest height?</h3>

We answered this in the last question. The t-value when h is at its highest is 12.

<h3>d)After how many seconds (round to nearest 100th) does the bullet hit the ground?</h3>

We have to solve for the values of t when h is 0 (when it touches the ground).

Set the equation to 0, and solve using the quadratic formula.

Quadratic formula: $x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$
$x = \frac{-384\pm\sqrt{384^2 - 4(-16)(50)}}{2(-16)}$
$x = \frac{-384\pm\sqrt{147456 +3200}}{-32}$
$x = \frac{-384\pm\sqrt{150656}}{-32}$
$x = \frac{-384\pm388.14}{-32}$
$x = -\frac{4.14}{32}, x = \frac{772.14}{32}$

We are only going to take the positive solution, as we can't have a negative time. The solution that doesn't work is called an extraneous solution.

$x = \frac{772.14}{32}$
$x = 24.13$

It takes approximately 24.13 seconds for the bullet to hit the ground.

6 0

3 years ago